1. 无重复 Suppose a sorted array is rotated at some pivot unknown to you beforehand. (i.e.,0 1 2 4 5 6 7might become4 5 6 7 0 1 2). Find the minimum element. You may assume no duplicate exists in the array. 思路:这个是找最小,和找指定数字其实差不多的。画个示意图吧 二分...
Suppose a sorted array is rotated at some pivot unknown to you beforehand. (i.e., 0 1 2 4 5 6 7 might become 4 5 6 7 0 1 2). Find the minimum element. The array may contain duplicates. 1classSolution {2public:3intfindMin(vector<int> &num) {4intlow =0;5inthigh = num.si...
Find the minimum element. You may assume no duplicate exists in the array. 本题难度Medium。 二分查找法 【复杂度】 时间O(N) 空间 O(N) 【思路】 题目假设:You may assume no duplicate exists in the array. 这道题与其他Rotated Sorted Array题一样可以用改良的二分查找法来做。 原则是只要一直...
但这样会有一个问题的,对于下边的例子,就会遇到死循环了。 问题出在,当数组剩两个的时候,mid = (start + end)/ 2,mid取的就是start。上图的例子,mid > end, 更新start = mid,start位置并不会变化。那么下一次mid的值也不会变,就死循环了。所以,我们要更新start = mid + 1,同时也使得start指向了最...
Description Suppose an array sorted in ascending order is rotated at some pivot unknown to you beforehand. (i.e., [0,1,2,4,5,6,7] might become [4,5,6,7,0,1,2]). Find the minimum element. You may assume no duplicate exists in the array. ...
Notice that rotating an array [a[0], a[1], a[2], ..., a[n-1]] 1 time results in the array [a[n-1], a[0], a[1], a[2], ..., a[n-2]]. Given the sorted rotated array nums of unique elements, return the minimum element of this array. ...
My code: My test result: 这不是一个好方法。下面介绍 binary search 版方法。 My code: My test result: 一下子快...
153. Find Minimum in Rotated Sorted Array 题目 Suppose an array sorted in ascending order is rotated at some pivot unknown to you beforehand. (i.e.,[0,1,2,4,5,6,7]might become[4,5,6,7,0,1,2]). Find the min element.
The array may contain duplicates. 这道题是Search in Rotated Sorted Array的扩展,思路在Find Minimum in Rotated Sorted Array中已经介绍过了,和Find Minimum in Rotated Sorted Array唯一的区别是这道题目中元素会有重复的情况出现。不过正是因为这个条件的出现,影响到了算法的时间复杂度。原来我们是依靠中间和...
Here, we are going to find the solution to find the minimum in rotated sorted array with C++ implementation.