Suppose a sorted array is rotated at some pivot unknown to you beforehand. (i.e.,0 1 2 4 5 6 7might become4 5 6 7 0 1 2). Find the minimum element. You may assume no duplicate exists in the array. 二、分析 这题难度有,因为他默认的是数组中所有的元素是不同的。只有分为两种情况...
Leetcode Find Minimum in Rotated Sorted Array 题目大意: 对一个有序数组翻转, 就是随机取前K个数,移动到数组的后面,然后让你找出最小的那个数。注意,K有可能是0,也就是没有翻转。 毫无疑问,遍历一次肯定能够找到,但这样时间复杂度是O(n)。假设你在面试的时候遇到这种问题,你这样回答面试官肯定不会惬意的。
但这样会有一个问题的,对于下边的例子,就会遇到死循环了。 问题出在,当数组剩两个的时候,mid = (start + end)/ 2,mid取的就是start。上图的例子,mid > end, 更新start = mid,start位置并不会变化。那么下一次mid的值也不会变,就死循环了。所以,我们要更新start = mid + 1,同时也使得start指向了最...
这里的话,就需要考虑如果mid == end的话,我们该怎么做。代码框架也就出来了。 publicintfindMin(int[]nums){intstart=0;intend=nums.length-1;while(start<end){intmid=(start+end)>>>1;if(nums[mid]>nums[end]){start=mid+1;}elseif(nums[mid]<nums[end]){end=mid;}else{//添加代码}}returnnum...
Find Minimum in Rotated Sorted Array -- LeetCode 这道题是Search in Rotated Sorted Array的扩展,差别就是如今不是找一个目标值了,而是在bst中找最小的元素。主要思路还是跟Search in Rotated Sorted Array差点儿相同。还是通过左边界和中间的大小关系来得到左边或者右边有序的信息。假设左半边有序。那么左...
Find Minumu in Rotated Sorted Array https://leetcode.com/problems/find-minimum-in-rotated-sorted-array/ 对于一个有序数组,将其元素以某一个元素为轴进行旋转,比如[0,1,2,3,4,5,6,7]可能会变成[4,5,6,7,0,1,2,3] 求这个经过旋转的数组的最小值,这里假设数组中没有重复值...
Notice that rotating an array [a[0], a[1], a[2], ..., a[n-1]] 1 time results in the array [a[n-1], a[0], a[1], a[2], ..., a[n-2]]. Given the sorted rotated array nums of unique elements, return the minimum element of this array. ...
153. Find Minimum in Rotated Sorted Array,classSolution{public:intfindMin(vector<int>&nums){for(inti=1;i<nums.size();++i){if(nums[i]<nums[i-1])returnnums[i];}retur
Here, we are going to find the solution to find the minimum in rotated sorted array with C++ implementation.
Set operations (on sorted ranges) merge inplace_merge set_difference set_intersection set_symmetric_difference set_union includes Heap operations is_heap (C++11) is_heap_until (C++11) make_heap sort_heap push_heap pop_heap Minimum/maximum operations ...