Can you solve this real interview question? Find Minimum in Rotated Sorted Array - Suppose an array of length n sorted in ascending order is rotated between 1 and n times. For example, the array nums = [0,1,2,4,5,6,7] might become: * [4,5,6,7,0,1,2] if
Suppose a sorted array is rotated at some pivot unknown to you beforehand. (i.e.,0 1 2 4 5 6 7might become4 5 6 7 0 1 2). Find the minimum element. You may assume no duplicate exists in the array. 二、分析 这题难度有,因为他默认的是数组中所有的元素是不同的。只有分为两种情况...
所以就随便搜了下Garnker的,知道是Search in Rotated Sorted Array,那题是找目标值。这里是找最小值。 我是这样想的,分为几部分, 1.如果左边的值等于中间的值了,那么就剩下两个数要判断了,而且是相邻的。 2.如果中间的值大于左边的值,那么最小值肯定不是在最左边就只在右边一块了。 3.如果中间值小于左...
而Find Minimum in Rotated Sorted Array II这道题这考虑了元素反复的情况,这里仅仅是为了算法更加一般性。就把那个情况也包括进来,有兴趣的朋友能够看看Find Minimum in Rotated Sorted Array II对反复元素的分析哈。
mid < start: 最小值在左半部分。 无论大于还是小于,最小值都在左半部分,所以 mid 和start 比较是不可取的。 mid 和end 比较 mid < end:最小值在左半部分。 mid > end:最小值在右半部分。 所以我们只需要把 mid 和end 比较,mid < end 丢弃右半部分(更新 end = mid),mid > end 丢弃左半部分(...
This is a follow up problem to Find Minimum in Rotated Sorted Array. Would allow duplicates affect the run-time complexity? How and why? 描述 假设按照升序排序的数组在预先未知的某个点上进行了旋转。 ( 例如,数组 [0,1,2,4,5,6,7] 可能变为 [4,5,6,7,0,1,2] )。
153. Find Minimum in Rotated Sorted Array 题目 Suppose an array sorted in ascending order is rotated at some pivot unknown to you beforehand. (i.e.,[0,1,2,4,5,6,7]might become[4,5,6,7,0,1,2]). Find the min element.
Search in rotated sorted array - Leetcode 33 - Python 呼吸的chou 0 0 Code-It-Yourself! Tetris - Programming from Scratch (Quick and Simple C++) 呼吸的chou 4 0 Decode Ways - Dynamic Programming - Leetcode 91 - Python 呼吸的chou 0 0 ...
Notice that rotating an array [a[0], a[1], a[2], ..., a[n-1]] 1 time results in the array [a[n-1], a[0], a[1], a[2], ..., a[n-2]]. Given the sorted rotated array nums of unique elements, return the minimum element of this array. ...
153. Find Minimum in Rotated Sorted Array 没有重复的情况。当然要用二分查找,我永远也忘不了头条第一挂,竟然是这么简单的题没整明白。 ...