https://github.com/grandyang/leetcode/issues/366 类似题目: Maximum Depth of Binary Tree Minimum Height Trees 参考资料: https://leetcode.com/problems/find-leaves-of-binary-tree/ https://leetcode.com/problems/find-leaves
LeetCode 366. Find Leaves of Binary Tree 实质就是求每个节点的最大深度。用一个hash表记录,最后输出。 classSolution {public: unordered_map<TreeNode *,int> hash;//record the level from bottomvector<vector<int>> findLeaves(TreeNode*root) { vector<vector<int>>res; dfs(root);//for (auto x:...
366. Find Leaves of Binary Tree https://leetcode.com/problems/find-leaves-of-binary-tree/description/ Given a binary tree, collect a tree’s nodes as if you were doing this: Collect and remove all leaves, repeat until the tree ......
Can you solve this real interview question? Find a Corresponding Node of a Binary Tree in a Clone of That Tree - Given two binary trees original and cloned and given a reference to a node target in the original tree. The cloned tree is a copy of the ori
[leetcode] 652. Find Duplicate Subtrees Description Given a binary tree, return all duplicate subtrees. For each kind of duplicate subtrees, you only need to return the root node of any one of them. Two trees are duplicate if they have the same structure with same node values....
leetcode 501. Find Mode in Binary Search Tree Given a binary search tree (BST) with duplicates, find all themode(s)(the most frequently occurred element) in the given BST. Assume a BST is defined as follows: The left subtree of a node contains only nodes with keysless than or equal ...
(1) class BinaryTree: def __init__(self, value, left=None, right=None, parent=None): self.value = value self.left = left self.right = right self.parent = parent def findSuccessor(tree, node): if node.right is not None: return getLeftmostChild(node.right) return getRightmostParent(...
Given two binary trees original and cloned and given a reference to a node target in the original tree. The cloned tree is a copy of the original tree. Return a reference to the same node in the cloned tree. Note that you are not allowed to change any of the two trees or the target...
Note:Time complexity should be O(height of tree). Example: root = [5,3,6,2,4,null,7] key = 3 5 / \ 3 6 / \ \ 2 4 7 Given key to delete is 3. So we find the node with value 3 and delete it. One valid answer is [5,4,6,2,null,null,7], shown in the following ...
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