英文coding面试练习 day3-1 | Leetcode662 Maximum Width of Binary Tree, 视频播放量 29、弹幕量 0、点赞数 0、投硬币枚数 0、收藏人数 0、转发人数 0, 视频作者 Rollwithlife, 作者简介 To remember,相关视频:英文coding面试练习 day3-2 | Leetcode907 Sum of Subarray
Can you solve this real interview question? Maximum Width of Binary Tree - Given the root of a binary tree, return the maximum width of the given tree. The maximum width of a tree is the maximum width among all levels. The width of one level is defined
Given the root of a binary tree, return its maximum depth.A binary tree's maximum depth is the number of nodes along the longest path from the root node down to the farthest leaf node. 英文版地址 leetcode.com/problems/m 中文版描述 给定一个二叉树,找出其最大深度。二叉树的深度为根节点到...
int maxDepth(TreeNode *root) { int height = 0,rowCount = 1; if(root == NULL){ return 0; } //创建队列 queue<treenode*> queue; //加入根节点 queue.push(root); //层次遍历 while(!queue.empty()){ //队列头元素 TreeNode *node = queue.front(); //出队列 queue.pop(); //一层的...
The left subtree is the maximum tree constructed from left part subarray divided by the maximum number. The right subtree is the maximum tree constructed from right part subarray divided by the maximum number. Construct the maximum tree by the given array and output the root node of this tree...
* Definition for a binary tree node. * struct TreeNode { * int val; * TreeNode *left; * TreeNode *right; * TreeNode(int x) : val(x), left(NULL), right(NULL) {} * }; */ classSolution { public: intmaxDepth(TreeNode* root) { ...
https://leetcode.com/problems/maximum-depth-of-binary-tree/ 题目: Given a binary tree, find its maximum depth. The maximum depth is the number of nodes along the longest path from the root node down to the farthest leaf node. 思路: ...
My code: /** * Definition for a binary tree node. * public class TreeNode { * int val; * TreeNode left; * TreeNode right; * TreeNode(int x) { val = x; } * } */publicclassSolution{publicintmaxDepth(TreeNoderoot){if(root==null){return0;}intleft=maxDepth(root.left);intright...
http://www.programcreek.com/2013/02/leetcode-binary-tree-maximum-path-sum-java/ 另外,这道题目的BST条件,似乎没什么用。因为如果全是负数,BST也没帮助了。 ** 总结: pre-order -> top-down post-order -> bottom-up in-order -> ? level-order -> bfs ...
int maxDepth(TreeNode *root) { int height = 0,rowCount = 1; if(root == NULL){ return 0; } //创建队列 queue<TreeNode*> queue; //添加根节点 queue.push(root); //层次遍历 while(!queue.empty()){ //队列头元素 TreeNode *node = queue.front(); ...