int BST_Insert(BSTree &T, int k, Node* parent=NULL) { if(T == NULL) { T = (BSTree)malloc(sizeof(Node)); T->key = k; T->left = NULL; T->right = NULL; T->parent = parent; return 1; // 返回1表示成功 }else if(k == T->
classSolution:defdiameterOfBinaryTree(self,root:Optional[TreeNode])->int:self.res =0# 0或1都可以defdepth(root):# 访问到空节点了,返回0ifnotroot:return0# 左儿子为根的子树的深度leftDep = depth(root.left)# 右儿子为根的子树的深度rightDep = depth(root.right)# 计算d_node即L+R+1 并更新re...
class Solution { public int widthOfBinaryTree(TreeNode root) { int result = 0; Deque<TreeNode> deque = new ArrayDeque(); deque.addLast(new TreeNode(1, root.left, root.right)); while(!deque.isEmpty()) { int count = deque.size(), startIndex = -1, endIndex = -1; for (int i ...
int*returnSize){//每次调用函数时,都要把i初始化//如果没有初始化,则i会一直叠加,无法重复使用i=0;// 调用TreeSize函数计算二叉树的节点数int size=TreeSize(root);// 动态分配结果数组,大小为节点数int*a=(int*)malloc(size*sizeof(int));// 调用辅助函数_prevOrder执行前序遍历,填充数组a_prevOrder(...
Map<Integer, Integer> map; public TreeNode constructMaximumBinaryTree(int[] nums) { return constructTree(nums, 0, nums.length); } public TreeNode constructTree(int[] nums, int leftIndex, int rightIndex){ //终止条件 if (rightIndex-leftIndex<1) return null; if (rightIndex-leftIndex...
Size-1);}//pBegin和pEnd分别是当前前序数组的起点和终点 iBegin和iEnd分别是当前中序数组的起点和终点TreeNode*buildTree(int pBegin,int pEnd,int iBegin,int iEnd){//如果指针错位,说明当前位空节点if(pBegin>pEnd||iBegin>iEnd)returnNULL;//构造当前根节点---当前前序数组的起点TreeNode*root=newTree...
You are given a binary tree in which each node contains an integer value.Find the number of paths that sum to a given value.The path does not need to start or end at the root or a leaf, but it must go downwards (traveling only from parent nodes to child nodes). The tree has no...
104. Maximum Depth of Binary Tree Given a binary tree, find its maximum depth. The maximum depth is the number of nodes along the longest path from the root node down to the farthest leaf node. 同Minimum Depth of Binary Tree求解类似。http://qiaopeng688.blog.51cto.com/3572484/1835237 ...
类似于,给你一个 pre-order的访问顺序的数组,恢复出这个普通的,general binary tree. 依旧采用dfs 设置一个全局变量 curr = 0 然后,每次进入dfs中时, curr++;if(treeArr[curr].equals("n")){...}else{TreeNoderoot=newTreeNode(val);root.left=dfs(...);root.right=dfs(...);returnroot;} ...
LeetCode 104. Maximum Depth of Binary Tree Given a binary tree, find its maximum depth. The maximum depth is the number of nodes along the longest path from the root node down to the farthest leaf node. MaximumDepthofBinaryTree.jpg