classSolution {public:intdiameterOfBinaryTree(TreeNode*root) { diameterCore(root);returndiameter; }intdiameterCore(TreeNode*root){if(root ==NULL)return0;intleft = diameterCore(root->left);intright = diameterCore(root->right); diameter= max(diameter,left +right);returnleft > right ? left +...
LeetCode 543. Diameter of Binary Tree 二叉树的直径 (C++/Java) LeetCode 687. Longest Univalue Path 最长同值路径 (C++/Java) 那么这道题还是从根节点递归求解,当前结点的最大路径,是当前节点的值加上左右孩子的最大路径,同时和全局的最大值进行比较,更新最大值,而作为返回值时,需要在左右孩子中选取最大...
Leetcode 543. Diameter of Binary Tree 题目描述:找出二叉树的最长直径(也就是所以节点连成最长的路径长度) 题目链接:Leetcode 543. Diameter of Binary Tree 题目思路:用到的就是经典的递归返回值的形式,不断返回左子树和右子树的深度,然后过程中更新最长的路径。 代码如下 参考链接 543. Diameter of Binary Tr...
0515-find-the-largest-value-in-each-tree-row.cpp 0518-coin-change-ii.cpp 0523-continuous-subarray-sum.cpp 0535-encode-and-decode-tinyurl.cpp 0538-convert-bst-to-greater-tree.cpp 0540-single-element-in-a-sorted-array.cpp 0543-diameter-of-binary-tree.cpp 0554-brick-wall.cpp 0560-subarray-su...
LeetCode之Binary Tree Maximum Path Sum 题目: Given a binary tree, find the maximum path sum. For this problem, a path is defined as any sequence of nodes from some starting node to any node in the tree along the parent-child connections. The path does not need to go through the root...
0543-diameter-of-binary-tree.cpp 0554-brick-wall.cpp 0560-subarray-sum-equals-k.cpp 0567-permutation-in-string.cpp 0572-subtree-of-another-tree.cpp 0605-can-place-flowers.cpp 0617-merge-two-binary-trees.cpp 0621-task-scheduler.cpp 0637-average-of-levels-in-binary-tree.cpp 0647-palindromic-...
跟[leetcode]543. Diameter of Binary Tree二叉树直径的思路基本一致。 代码 1classSolution {2publicintmaxPathSum(TreeNode root) {3//corner case4if(root ==null){return0;}5/*要么用个global variable放在class下,要么用长度为1的一维数组来存。6maxSum的value,可正可负,初始化为Integer.MIN_VALUE。7...
A path in a binary tree is a sequence of nodes where each pair of adjacent nodes in the sequence has an edge connecting them. A node can only appear in the sequence at most once. Note that the path does not need to pass through the root. ...
124. Binary Tree Maximum Path Sum; 543. Diameter of Binary Tree; 687. Longest Univalue Path;求二叉树的最大路径,路径和,相同值节点的最大路径。 解法:Binary Tree (二叉树) 模版:一棵树问题: 1def solve(root)2//无效节点处理3ifnot root:return...4//递归终点,base5iff(root):return...6//左...
Leetcode 559. Maximum Depth of N-ary Tree c++,如果本节点为空,返回0,否则返回 这棵树孩子中(找到每个节点的最大值,返回最大值+1即可,1是本节点的深度) /*// Definition for a Node.class Node {public:int val;vector<Node*> children;Node() {}Node(int _val) {val = _val;}Node(int _val...