Given an array of integers, 1 ≤ a[i] ≤ n (n = size of array), some elements appear twice and others appear once. Find all the elements that appear twice in this array. Could you do it without extra space and in O(n) runtime? Example: Input: [4,3,2,7,8,2,3,1] Output:...
时间复杂度:O(n),空间复杂度:O(1) funcfindDuplicates(nums []int)[]int{len:=len(nums)iflen<=1{returnnil} result := []int{} i :=0fori <len{ifi == nums[i] -1|| nums[i] ==0{ i++continue}ifnums[i] == nums[nums[i] -1] { result =append(result, nums[i]) nums[i] =...
Given an array of integers, 1 ≤ a[i] ≤n(n= size of array), some elements appear twice and others appear once. Find all the elements that appear twice in this array. Could you do it without extra space and in O(n) runtime? Example: Input: [4,3,2,7,8,2,3,1] Output: [2...
442. Find All Duplicates in an Array Given an array of integers, 1 ≤ a[i] ≤ n (n = size of array), some elements appear twice and others appear once. Find all the e...[leetcode] 442. Find All Duplicates in an Array 样例: Input: Output: 在数组中找出所有重复出现的数,要求时...
leetcode-442.Find All Duplicates in an Array 题目Given an array of integers, 1 ≤ a[i] ≤ n (n = size of array), some elements appear twice and others appear once. Find all the elements that appear twice in this array. Could you do it without......
与[LeetCode]Find All Numbers Disappeared in an Array几乎一样,不同之处就是找出twice的数。那么我们只要当nums[i]!=i+1时,然后又当nums[nums[i]-1]==nums[i]时,把nums[i]放入set即可。
442. **Find All Duplicates in an Array https://leetcode.com/problems/find-all-duplicates-in-an-array/description/ 题目描述 Given an array of integers, 1 ≤ a[i] ≤ n (n = size of array), some elements appear twice and others appear ...
Find All Duplicates in an Array 题目: Given an array of integers, 1 ≤ a[i] ≤ n (n = size of array), some elements appear twice and others appear once. Find all the elements that appear twice in this array. Could you do it 442. Find All Duplicates in an Array找出数组中...
To find which elements are duplicates, you could use this “array without duplicates” we got, and and remove each item it contains from the original array content:const yourArray = [1, 1, 2, 3, 4, 5, 5] const yourArrayWithoutDuplicates = [...new Set(yourArray)] let duplicates = ...
Finally, the last method to find duplicates in an array is to use the for loop.Here is an example that compares each element of the array with all other elements of the array to check if two values are the same using nested for loop:...