这道题给了我们一个数组,数组中的数字可能出现一次或两次,让我们找出所有出现两次的数字,由于之前做过一道类似的题目Find the Duplicate Number,所以不是完全无从下手。这类问题的一个重要条件就是1 ≤ a[i] ≤ n (n = size of array),不然很难在O(1)空间和O(n)时间内完成。首先来看一种正负替换的方法...
类似LeetCode 442. Find All Duplicates in an Array,由于元素是1~n,因此每个元素的值-1(映射到0~n-1)就可以直接当做下标。 classSolution {public:intfindDuplicate(vector<int>&nums) {for(inti=0;i<nums.size();++i){intindex=abs(nums[i])-1;if(nums[index]>0) nums[index]*=-1;elsereturnind...
Learn how to find duplicate values in a JavaScript array with this comprehensive guide, including examples and step-by-step instructions.
Given an array nums containing n + 1 integers where each integer is between 1 and n (inclusive), prove that at least one duplicate number must exist. Assume that there is only one duplicate number, find the duplicate one. Note: You must not modify the array (assume the array is read o...
Find the Duplicate Number Given an array nums containing n + 1 integers where each integer is between 1 and n (inclusive), prove that at least one duplicate number must exist. Assume that there is only one duplicate number, find the duplicate one. ...
[Leetcode] Find the Duplicate Number 找到重复数字 Find the Duplicate Number Given an array nums containing n + 1 integers where each integer is between 1 and n (inclusive), prove that at least one duplicate number must exist. Assume that there is only one duplicate number, find the ...
There are multiple methods available to check if an array contains duplicate values in JavaScript. You can use the indexOf() method, the Set object, or iteration to identify repeated items in an array.Set ObjectSet is a special data structure introduced in ES6 that stores a collection of ...
There is only one duplicate number in the array, but it could be repeated more than once. 思路: 不能修改数组所以不能排序,不能用额外的空间所以不能用HashMap,考虑鸽巢原理。数的范围在1~n之间,有n+1个数 猜测重复数为n/2,计算 数组中大于n/2的次数count,如果重复的数在n/2~n之间的话,count应...
Given an array nums containing n + 1 integers where each integer is between 1 and n (inclusive), prove that at least one duplicate number must exist. Assume that there is only one duplicate number, …
Given an array of integers, 1 ≤ a[i] ≤ n (n =size of array), some elements appear twice and others appear once. Find all the elements that appear twice inthisarray. Could youdoit without extra space and in O(n) runtime?Example: ...