Find the Duplicate Number: Given an array nums containing n + 1 integers where each integer is between 1 and n (inclusive), prove that at least one duplicate number must exist. Assume that there is only one duplicate number, find the duplicate one Note: You must not modify the array (...
Given an arraynumscontainingn+ 1 integers where each integer is between 1 andn(inclusive), prove that at least one duplicate number must exist. Assume that there is only one duplicate number, find the duplicate one. Example 1: Input:[1,3,4,2,2]Output: 2 Example 2: Input: [3,1,3,...
Given an array nums containing n + 1 integers where each integer is between 1 and n (inclusive), prove that at least one duplicate number must exist. Assume that there is only one duplicate number, find the duplicate one. Note: You must not modify the array (assume the array is read o...
Given an array nums containing n + 1 integers where each integer is between 1 and n (inclusive), prove that at least one duplicate number must exist. Assume that there is only one duplicate number, find the duplicate one. Note: You must not modify the array (assume the array is read o...
Find the Duplicate Number Given an array nums containing n + 1 integers where each integer is between 1 and n (inclusive), prove that at least one duplicate number must exist. Assume that there is only one duplicate number, find the duplicate one. Note: You must not modify the array (...
https://leetcode.com/problems/find-the-duplicate-number/题目找出一组无序数字中重复的数字。其中, 数组长度为 n+1,数字取值范围是 [1, n]有且只有一个数字重复要求数组不能改变(只读)只能使用 constant sp…
287 Find the Duplicate Number 寻找重复数 一个长度为 n + 1 的整形数组,其中的数字都在 1 到 n 之间,包括 1 和 n ,可知至少有一个重复的数字存在。假设只有一个数字重复,找出这个重复的数字。 注意: 不能更改数组内容(假设数组是只读的)。 只能使用恒定的额外空间,即要求空间复杂度是 O(1) 。
publicintfindDuplicate(int[]nums){intres=0;intn=nums.length;//统计每一列 1 的个数for(inti=0;i<32;i++){inta=0;intb=0;intmask=(1<<i);for(intj=0;j<n;j++){//统计原数组当前列 1 的个数if((nums[j]&mask)>0){a++;}//统计 1 到 n 序列中当前列 1 的个数if((j&mask)>0...
Leetcode 287. Find the Duplicate Number Given an array nums containing n + 1 integers where each integer is between 1 and n (inclusive), prove that at least one duplicate number must exist. Assume that there is only one duplicate number, fi......
There is only one duplicate number in the array, but it could be repeated more than once. 思路: 不能修改数组所以不能排序,不能用额外的空间所以不能用HashMap,考虑鸽巢原理。数的范围在1~n之间,有n+1个数 猜测重复数为n/2,计算 数组中大于n/2的次数count,如果重复的数在n/2~n之间的话,count应...