[Leetcode] Find the Duplicate Number 找到重复数字 Find the Duplicate Number Given an array nums containing n + 1 integers where each integer is between 1 and n (inclusive), prove that at least one duplicate number must exist. Assume that there is only one duplicate number, find the ...
Given an array nums containing n + 1 integers where each integer is between 1 and n (inclusive), prove that at least one duplicate number must exist. Assume that there is only one duplicate number, find the duplicate one.Note:You must not modify the array (assume the array is read only...
类似LeetCode 442. Find All Duplicates in an Array,由于元素是1~n,因此每个元素的值-1(映射到0~n-1)就可以直接当做下标。 classSolution {public:intfindDuplicate(vector<int>&nums) {for(inti=0;i<nums.size();++i){intindex=abs(nums[i])-1;if(nums[index]>0) nums[index]*=-1;elsereturnind...
[2,3] 这道题给了我们一个数组,数组中的数字可能出现一次或两次,让我们找出所有出现两次的数字,由于之前做过一道类似的题目Find the Duplicate Number,所以不是完全无从下手。这类问题的一个重要条件就是1 ≤ a[i] ≤ n (n = size of array),不然很难在O(1)空间和O(n)时间内完成。首先来看一种正负...
Leetcode 287. Find the Duplicate Number Given an array nums containing n + 1 integers where each integer is between 1 and n (inclusive), prove that at least one duplicate number must exist. Assume that there is only one duplicate number, find the duplicate one....
Find the Duplicate Number Given an array nums containing n + 1 integers where each integer is between 1 and n (inclusive), prove that at least one duplicate number must exist. Assume that there is only one duplicate number, find the duplicate one. ...
287. Find the Duplicate Number Given an arraynumscontainingn+ 1 integers where each integer is between 1 andn(inclusive), prove that at least one duplicate number must exist. Assume that there is only one duplicate number, find the duplicate one....
287. Find the Duplicate Number 题目 Given an array nums containing n + 1 integers where each integer is between 1 and n (inclusive), prove that at least one duplicate number must exist. Assume that there is only one duplicate number, find the duplicate one....
There is only one duplicate number in the array, but it could be repeated more than once. 题解: 自己的位运算写法超长度了。 classSolution{ public: intfindDuplicate(vector<int>&nums) { intn=nums.size(); longlongbit=0; for(inti=0;i<n;i++) { ...
Given an array nums containing n + 1 integers where each integer is between 1 and n (inclusive), prove that at least one duplicate number must exist. Assume that there is only one duplicate number, …