Given an array nums containing n + 1 integers where each integer is between 1 and n (inclusive), prove that at least one duplicate number must exist. Assume that there is only one duplicate number, find the duplicate one. Note: You must not modify the array (assume the array is read o...
Find the Duplicate Number Given an array nums containing n + 1 integers where each integer is between 1 and n (inclusive), prove that at least one duplicate number must exist. Assume that there is only one duplicate number, find the duplicate one. Note: You must not modify the array (as...
Given an arraynumscontainingn+ 1 integers where each integer is between 1 andn(inclusive), prove that at least one duplicate number must exist. Assume that there is only one duplicate number, find the duplicate one. Note: You must not modify the array (assume the array is read only). Yo...
[2,3] 这道题给了我们一个数组,数组中的数字可能出现一次或两次,让我们找出所有出现两次的数字,由于之前做过一道类似的题目Find the Duplicate Number,所以不是完全无从下手。这类问题的一个重要条件就是1 ≤ a[i] ≤ n (n = size of array),不然很难在O(1)空间和O(n)时间内完成。首先来看一种正负...
Find the Duplicate Number数组中重复的数 题意:数组中有1+n个数都是1到n之间,找出其中重复的。 解法一:二分搜索,先求出中点mid,然后遍历整个数组,统计所有小于等于mid的数的个数,如果个数小于等于mid,则说明重复值在[mid+1, n]之间,反之,重复值应在[1, mid-1]之间。 解法二:利用快慢指针,思路和带环...
- There is only one duplicate number in the array, but it could be repeated more than once. 代码如下: publicintfindDuplicate(int[] nums) {if(nums.length >1){intslow = nums[0];intfast = nums[nums[0]];//以下为求两个指针第一次相遇的点while(slow != fast){ ...
Write a Java program to find duplicate values in an array of integer values.Pictorial Presentation:Sample Solution:Java Code:// Import the Arrays class from the java.util package. import java.util.Arrays; // Define a class named Exercise12. public class Exercise12 { // The main method ...
287. Find the Duplicate Number 题目 Given an array nums containing n + 1 integers where each integer is between 1 and n (inclusive), prove that at least one duplicate number must exist. Assume that there is only one duplicate number, find the duplicate one....
How to find duplicate values in a JavaScript array - In this tutorial, we will discuss how we can find duplicate or repeating values in a JavaScript array using different methods or approaches to reach the solution to this problem. Below is the list of t
这是一个Java程序,用于解决LeetCode题目中的"Find the Duplicate Number"问题。该程序的主要功能是遍历数组,找出重复的数字并返回其索引。 以下是该程序的代码: public class FindDuplicate { public static int findDuplicate(int[] nums) { int n = nums.length; for (int i = 0; i < n - 1; i++)...