leetcode算法: Find All Duplicates in an Array Given an array of integers, 1 ≤ a[i] ≤ n (n = size of array), some elements appear twice and others appear once. Find all the elements that appear twice in this array. Could you do it without extra space and in O(n) runtime? Exa...
输出: [2,3] publicList<Integer> findDuplicates(int[] nums) { List<Integer> list =newArrayList<>(); Arrays.sort(nums);for(inti=1;i<nums.length;i++) {if(nums[i]==nums[i-1]) { list.add(nums[i]); } }returnlist; } publicList<Integer> findDuplicates(int[] nums) { List<Integer...
442. Find All Duplicates in an Array Given an array of integers, 1 ≤ a[i] ≤ n (n = size of array), some elements appear twice and others appear once. Find all the elements that appear twice in this array. Could you do it without extra space and in O(n) runtime? Example: ...
[leetcode]442. Find All Duplicates in an Array [leetcode]442. Find All Duplicates in an Array Analysis 周五ummmmmm—— [啊啊啊啊 paper结果要出来了,心塞] Given an array of integers, 1 ≤ a[i] ≤ n (n = size of array), some elements appear twice and......
Given an array of integers, 1 ≤ a[i] ≤n(n= size of array), some elements appear twice and others appear once. Find all the elements that appear twice in this array. Could you do it without extra space and in O(n) runtime?
442. Find All Duplicates in an Array 题目描述: Given an array of integers, 1 ≤ a[i] ≤n(n= size of array), some elements appeartwiceand others appearonce. Find all the elements that appeartwicein this array. Could you do it without extra space and in O(n) runtime?
442. **Find All Duplicates in an Array https://leetcode.com/problems/find-all-duplicates-in-an-array/description/ 题目描述 Given an array of integers, 1 ≤ a[i] ≤ n (n = size of array), some elements appear twice and others appear ...
问题描述: Given an array of integers where 1 ≤ a[i] ≤ n (n = size of array),some elements appear twice and others appear once. Find all the elements of [1, n] inclusive that do not appear in this ar... 查看原文 leetcode之Find All Duplicates in an Array 问题 问题描述: ...
const yourArray = [1, 1, 2, 3, 4, 5, 5] const yourArrayWithoutDuplicates = [...new Set(yourArray)] let duplicates = [...yourArray] yourArrayWithoutDuplicates.forEach((item) => { const i = duplicates.indexOf(item) duplicates = duplicates .slice(0, i) .concat(duplicates.slice(i...
Finally, the last method to find duplicates in an array is to use the for loop.Here is an example that compares each element of the array with all other elements of the array to check if two values are the same using nested for loop:...