If a function is given by f(x)=e^( x/7), which of the following is an equation of the line tangent to the graph of f(x) when f(x)=e? ( ) A. y-e= 17e(x-7) B. y-e=-7e(x-7) C. y-7=-7e(x-e) D. y-7= 17e(x-e)...
Find the equation of line tangent to the graph of f(x)=e+ln x at x=1? 答案 e是常数,f'(x)=1/x,所以切线在x=1点的斜率是1,在x=1点的函数值是e.So the equation of the tangent line of graph at x=1 is f(x)=x+e-1相关推荐 1Find the equation of line tangent to the grap...
EXAMPLE 7 Find the equation of the tangent line to the graph of y = tan x at the point (w/4, 1). 相关知识点: 试题来源: 解析 SOLUTION The derivative of y=tanxsin(dy)/(dx)=sec^2x . When x = #/4, the derivative is equal t sec^(2π)=(2/(√2))^2=2 = 2. Thus the ...
The point-slope equation can be used to calculate the equation of the tangent line. It is given by: y−y0=mLt(x0)(x−x0). Answer and Explanation:1 Let us find an equation of the line tangent to the graph off(x)=(...
英文的导数题Let f(x)=8x+20/(x^2).Then the equation of the tangent line to the graph of f(x)
题目翻译：下面哪一个选项是代表图像y=x＋e^x 在x＝0处的切线方程？解答:先求导 y'=1+e^x ， 当x=0时，y'=1+1=2 所以在x＝0这一点处切线的斜率是2 然后根据点（0，1）和斜率2 可以得到这条切线的方程 y=2x+1 答案选择e 对吗？
题的意思是：求f(x)=8/√(x^2+3x)在点(1,4)处的切线方程 重点是求函数在x=1处的f'(x)直接求导很麻烦，可采用对数求导法，lnf(x)=ln8-(ln(x^2+3x))/2 两边同时对x求导，f'(x)/f(x)=-(2x+3)/2(x^2+3x)把x=1,f(x)=4带入，得 f'(x)=-5/2 可以求出切线方程为y...
Find an equation of the tangent line to the graph of the function {eq}f {/eq} defined by the equation at the indicated locations: {eq}x^2 + y^2 = 9 {/eq}. a) {eq}x = 0 {/eq}. b) {eq}x = 3 {/eq}. Tangen...
Use implicit differentiation to find an equation of the tangent line to the graph of the equation at the given point., (0,1) 答案 y=(-e-1)x+1 相关推荐 1Use implicit differentiation to find an equation of the tangent line to the graph of the equation at the given point., (0,1) ...
英文的导数题Let f(x)=8x+20/(x^2).Then the equation of the tangent line to the graph of f(x) at the point(2,21) is given by Y=mx+b for m=?b=?