Find the equation of line tangent to the graph of f(x)=e+ln x at x=1? 答案 e是常数,f'(x)=1/x,所以切线在x=1点的斜率是1,在x=1点的函数值是e.So the equation of the tangent line of graph at x=1 is f(x)=x+e-1相关推荐 1Find the equation of line tangent to the grap...
关于导数数学题If the line tangent to the graph of the function f at the point (1,7)passes through the point (-2,-2)then f ' (1) is ( )A.-5 B.1 C.3 D.7 E.undefined 答案 在(1,7)点的切线经过点(-2,-2)切线斜率k=(-2-7)/(-2-1)=3所以函数在(1,7)点的导数值为3于是...
百度试题 结果1 题目 What is the maximum slope of the line tangent to the graph of f(x) = 3x= − 2x3? A: B: C: D: 相关知识点: 试题来源: 解析 BNone 反馈 收藏
The point-slope equation can be used to calculate the equation of the tangent line. It is given by: y−y0=mLt(x0)(x−x0). Answer and Explanation:1 Let us find an equation of the line tangent to the graph off(x)=(...
题目【题目】Line i is tangent to the graph of a function fat the point (0,1). If f is twice differentiablewith f'(0)=2 and f"(0)=3, what is the approzimate value of f(0.) using line i? (A.0.1B.0.2C.1.2D.2.1 相关知识点: ...
题目翻译：下面哪一个选项是代表图像y=x＋e^x 在x＝0处的切线方程？解答:先求导 y'=1+e^x ， 当x=0时，y'=1+1=2 所以在x＝0这一点处切线的斜率是2 然后根据点（0，1）和斜率2 可以得到这条切线的方程 y=2x+1 答案选择e 对吗？
EXAMPLE 7 Find the equation of the tangent line to the graph of y = tan x at the point (w/4, 1). 相关知识点: 试题来源: 解析 SOLUTION The derivative of y=tanxsin(dy)/(dx)=sec^2x . When x = #/4, the derivative is equal t sec^(2π)=(2/(√2))^2=2 = 2. Thus the ...
Find the slope of the line tangent to the graph of y3−x2y+4x=7 at the point (-2,3). Implicit Differentiation:Recall that the derivative of a function at a point is equal to the value of the slope of the line tangent to the curve at that point. So ...
Answer to: Let L be the tangent line to the graph of the function y = ex at the point (a, b). Show that the distance between a and c is always...
Findf′(x)and find the equation of the line tangent to the graph offatx=2. f(x)=(1+5x)(5−2x) Equation of a Tangent Line: Determining the equation of a tangent line to a function is one of the applications of a function's derivative. This is because...