Find the tangent line to the graph of the given equation at the indicated point. {eq}x^2y^2-9x^2-4y^2=0, \ (-4, 2\sqrt 3) {/eq} Slopes of Tangent: The point of contact is the point in the curve where the tangent line equation is to be found. If the implicit...
Answer to: The tangent line to the graph of a function h at the point x=-5 is y=-(2x+14). Find the tangent line to the graph of y=xh(x) at x=-5. By...
题的意思是：求f(x)=8/√(x^2+3x)在点(1,4)处的切线方程 重点是求函数在x=1处的f'(x)直接求导很麻烦，可采用对数求导法，lnf(x)=ln8-(ln(x^2+3x))/2 两边同时对x求导，f'(x)/f(x)=-(2x+3)/2(x^2+3x)把x=1,f(x)=4带入，得 f'(x)=-5/2 可以求出切线方程为y...
EXAMPLE 7 Find the equation of the tangent line to the graph of y = tan x at the point (w/4, 1). 相关知识点: 试题来源: 解析 SOLUTION The derivative of y=tanxsin(dy)/(dx)=sec^2x . When x = #/4, the derivative is equal t sec^(2π)=(2/(√2))^2=2 = 2. Thus the ...
Find the line that is tangent to the graph of the equation {eq}3xy + 2x^2 y + xy^3 + y = 1 {/eq} at the point {eq}(0, 1) {/eq}. Tangent: The tangent to any given curve can be outlined as a line that touches the curve at only...
Find the equation of line tangent to the graph of f(x)=e+ln x at x=1? 答案 e是常数,f'(x)=1/x,所以切线在x=1点的斜率是1,在x=1点的函数值是e.So the equation of the tangent line of graph at x=1 is f(x)=x+e-1相关推荐 1Find the equation of line tangent to the grap...
Find an equation for the tangent line to the graph ofy=1x+4at the point on the graph wherex=9. Tangent Line: There is more possibility that a line intersects a curve at more than one points. But, sometimes there exist a line that touches the ...
结果1 题目【题目 】Use implicit differentiation to find an equatio n of the tangent line to the graph of the equa tion at the given point.xe^y+ye^x=1 , (0, 1) 相关知识点: 试题来源: 解析 【解析】 y=(-e-1)r+1 反馈 收藏 ...
Use implicit differentiation to find an equation of the tangent line to the graph of the equation at the given point., (0,1) 答案 y=(-e-1)x+1 相关推荐 1Use implicit differentiation to find an equation of the tangent line to the graph of the equation at the given point., (0,1) ...
Question: Find the equation of the tangent line to the graph of g(x)=f'(x) at x=-1 when f(x)=8x3+5x2+7x.(Express numbers in exact form. Use symbolic notation and fractions where needed. Express equation in terms of y and...