代码(Python3) class Solution: def divide(self, dividend: int, divisor: int) -> int: # 只有这种情况会出现溢出, # 因为 32 位有符号整数的范围是 [-(2 ^ 31), 2 ^ 31 - 1] , # 此时结果为 2 ^ 31 ,超过了 32 位有妇好整数的最大值, # 需要返回 2 ^ 31 - 1 。 if divisor == ...
https://oj.leetcode.com/problems/divide-two-integers/ Divide two integers without using multiplication, division and mod operator. If it is overflow, return MAX_INT. ===Comments by Dabay=== 先确定符号。 做除法式子: 一个字符串保存商,一个字符串保存余数。 计算每一位商的时候,用余数来减除数...
https://leetcode.com/problems/divide-two-integers/ 题意分析: 不用乘法,除法和mod运算来实现一个除法。如果数值超过了int类型那么返回int的最大值。 题目思路: 初步来说,有两个做法。 ①模拟除法的过程,从高位开始除,不够先右挪一位。这种方法首先要将每一位的数字都先拿出来,由于最大int类型,所以输入的...
LeetCode 29. Divide Two Integers Description Given two integers dividend and divisor, divide two integers without using multiplication, division, and mod operator. The integer division should truncate toward zero, which means losing its fractional part. For example, 8.345 would be truncated to 8, a...
29. Divide Two Integers 给定两个整数,被除数 dividend 和除数 divisor。将两数相除,要求不使用乘法、除法和 mod 运算符。 返回被除数 dividend 除以除数 divisor 得到的商。 整数除法的结果应当截去(truncate)其小数部分,例如:truncate(8.345) = 8 以及 truncate(-2.7335) = -2 ...
29. Divide Two Integers刷题笔记 1. 2. 3. 4. 5. 6. 7. 8. 9. 10. 11. 12. 13. 14. 15.
Divide two integers without using multiplication, division and mod operator. If it is overflow, return MAX_INT. class Solution(object): def divide(self, dividend, divisor): """ :type dividend: int :type divisor: int :rtype: int """ ...
29 Divide Two Integers 两数相除 Description: Given two integers dividend and divisor, divide two integers without using multiplication, division and mod operator. Return the quotient after dividing dividend by divisor. The integer division should truncate toward zero. ...
原题地址:https://oj.leetcode.com/problems/divide-two-integers/ 题意:Divide two integers without using multiplication, division and mod operator. 解题思路:不许用乘、除和求余实现两数的相除。那就只能用加和减了。正常思路是被除数一个一个的减除数,直到剩下的数比除数小为止,就得到了结果。这样是...
leetcode Divide Two Integers python classSolution(object):defdivide(self, dividend, divisor):""":type dividend: int :type divisor: int :rtype: int"""flag=-1if( dividend > 0anddivisor >0 )or( dividend < 0anddivisor <0 ): flag=1dividend=abs(dividend)...