int divide(int dividend, intdivisor) { if(divisor == 0)return MAX_INT;//除数为零 if(divisor == -1 && dividend == -2147483648)return MAX_INT;//被除数为int的最小数(-2147483648),除数为-1,此时由于int整数最大只能为2147483647,会溢出 int fla
leetcode-【中等题】Divide Two Integers 题目Divide two integers without using multiplication, division and mod operator.If it is overflow, return MAX_INT链接https://leetcode.com/problems/divide-two-integers/答案1、int的最大值MAX_INT为power(2,31)-1 = 21474836472、int的最小值MIN_INT为-power(2...
[LeetCode] Divide Two Integers 两数相除 Divide two integers without using multiplication, division and mod operator. If it is overflow, retu ... [LeetCode] 29. Divide Two Integers 两数相除 Given two integers dividend and divisor, divide two integers without using multiplication, division .....
题目链接: Divide Two Integers : https://leetcode.com/problems/divide-two-integers/ 两数相除: https://leetcode.cn/problems/divide-two-integers/ LeetCode 日更第136天,感谢阅读至此的你 欢迎点赞、收藏鼓励支持小满
Given two integers dividend and divisor, divide two integers without using multiplication, division and mod operator. Return the quotient after dividing dividend by divisor. The integer division should truncate toward zero. Example 1: Input: dividend = 10, divisor = 3 ...
Leetcode每日一题:29.divide-two-integers(两数相除),参照评论大佬思路学到了:/***解题思路:这题是除法,所以先普及下除法术语*商,公式是:(被除数-余数)÷除数=商,记作:被除数÷除数=商...余数,是一种数学术语。*在一个除法算式里,被除数、余数、除数和商的关系为
题目描述(中等难度) 两个数相除,给出商。不能用乘法,除法和模操作。 本来觉得这道题蛮简单的,记录下自己的坎坷历程。 尝试1 先确定商的符号,然后把被除数和除数通通转为正数,然后用被除数不停的减除数,直到小于除数的时候,用一个计数遍历记录总共减了多少次,即为
Divide Two Integers 标签: C++ 算法 LeetCode 每日算法——leetcode系列 问题Divide Two Integers Difficulty:Medium Divide two integers without using multiplication, division and mod operator. If it is overflow, return MAX_INT. classSolution{public:intdivide(intdividend,intdivisor){}};...
LeetCode 29. Divide Two Integers Description Given two integers dividend and divisor, divide two integers without using multiplication, division, and mod operator. The integer division should truncate toward zero, which means losing its fractional part. For example, 8.345 would be truncated to 8, ...
LeetCode 29 Divide Two Integers(两个整数相除)(*) 翻译 不用乘法、除法、取余操作,将两个数相除。 如果它溢出了,返回MAX_INT 原文 Dividetwointegerswithoutusingmultiplication, divisionandmodoperator. Ifitis overflow,returnMAX_INT. 代码 一心扑到了递归上,可惜没能写出来………烦躁至极还是找了别人的答案...