leetcode 29. 两数相除(Divide Two Integers) 题目描述: 给定两个整数,被除数dividend和除数divisor。将两数相除,要求不使用乘法、除法和 mod 运算符。 返回被除数dividend除以除数divisor得到的商。 示例1: 输入: dividend = 10, divisor = 3输出: 3 示例2: 输入: dividend = 7, divisor = -3输出: -2 ...
LeetCode OJ:Divide Two Integers(两数相除) Divide two integers without using multiplication, division and mod operator. If it is overflow, return MAX_INT. 两数相除,不能用*,/,% 那么只能用位移运算了,注意边界条件防止溢出,代码如下: 1classSolution {2public:3intdivide(intdividend,intdivisor) {4in...
1publicclassSolution {2publicintdivide(intdividend,intdivisor) {3//被除数为0或者Integer.MIN_VALUE / -1的情况。4if(divisor == 0 || (dividend ==Integer.MIN_VALUE5&& divisor == -1))returnInteger.MAX_VALUE;6intres = 0;7//符号8intsign = (dividend > 0 && divisor < 0) || (dividend ...
Divide Two Integers Divide two integers without using multiplication, division and mod operator. SOLUTION 1 1. 基本思想是不断地减掉除数,直到为0为止。但是这样会太慢。 2. 我们可以使用2分法来加速这个过程。不断对除数*2,直到它比被除数还大为止。加倍的同时,也记录下cnt,将被除数减掉加倍后的值,并且...
classSolution {public:longlongabs(intn) {longlongn1=n;if(n1<0) n1=-1*n1;returnn1; }intdivide(intdividend,intdivisor) { long longres=0;intint_min=1<<31;intint_max=(int_min>>31) ^int_min;longlongdivid =dividend;longlongdivis =divisor;boolresNeg =false;if((divid>0&& divis<0)...
乘风破浪:LeetCode真题_029_Divide Two Integers 一、前言 两个整数相除,不能使用乘法除法和取余运算。那么就只能想想移位运算和加减法运算了。 二、Divide Two Integers 2.1 问题 2.2 分析与解决 通过分析,我们可以想到,如果使用加法,一次次的减下去,每减一次就加一,直到最后的减数小于除数。但是这样的时间复杂度将...
LeetCode:Divide Two Integers 题目链接 Divide two integers without using multiplication, division and mod operator. 最直观的方法是,用被除数逐个的减去除数,直到被除数小于0。这样做会超时。本文地址 那么如果每次不仅仅减去1个除数,计算速度就会增加,但是题目不能使用乘法,因此不能减去k*除数,我们可以对除数进行...
例题3Divide Two Integers Divide two integers without using multiplication, division and mod operator. classSolution {public:intdivide(intdividend,intdivisor) { } }; 这道题相较于前一道稍复杂些。首先考虑divisor为0的情况,再考虑负数的情况。
[leetcode]29. Divide Two Integers两整数相除 Given two integers dividend and divisor, divide two integers without using multiplication, divisio ... [leetcode]29. Divide Two Integers 两整数相除 Given two integers dividend and divisor, divide two integers without using multiplication, division ......
LeetCode-Divide Two Integers Description: Given two integers dividend and divisor, divide two integers without using multiplication, division and mod operator. Return the quotient after dividing dividend by divisor. The integer division should truncate toward zero....