Given an encoded string, return its decoded string. The encoding rule is:k[encoded_string], where theencoded_stringinside the square brackets is being repeated exactlyktimes. Note thatkis guaranteed to be a positive integer. You may assume that the input string is always valid; there are no ...
*/stringdecodeString3(string s){intlen = s.size();if(len ==0) {return""; }inti =0;returndecodeHelper(s, i); }stringdecodeHelper(string s,int& i){ string result ="";intlen = s.size();while(i < len && s[i] !=']') {// 非数字而是字符的情况下if(s[i] <'0'|| s[i...
https://leetcode.com/problems/decode-string/ https://leetcode.com/problems/decode-string/discuss/87728/share-my-c-solution https://leetcode.com/problems/decode-string/discuss/87543/0ms-simple-C%2B%2B-solution LeetCode All in One 题目讲解汇总(持续更新中...)...
Given an encoded string, return its decoded string. The encoding rule is: k[encoded_string], where theencoded_stringinside the square brackets is being repeated exactlyktimes. Note thatkis guaranteed to be a positive integer. You may assume that the input string is always valid;...
LeetCode_394. Decode String 字符串解码 题目描述: 思路:首先想到使用栈来存放数据,一个数字栈,一个字符栈。 1.当遇到数字的时候就统计数字(注意数字可能会超过一位数) 2.当遇到字符的时候就记录下来 3.遇到’[‘时,就说明新的数字和字符串要开始了,需要将已经记录好的数字和字符串放到对应的堆栈当中...
==0{chs[ch-'a']=originorigin+=1}}// 解密 messageans:=make([]byte,len(message))fori,ch:=rangemessage{// 如果 ch 不是空格,则解密ifch==' '{// 如果 ch 是空格,则依旧为空格ans[i]=' '}else{// // 如果 ch 是字母,则设置为对照表中的字母ans[i]=chs[ch-'a']}}returnstring(...
public int numDecodings(String s) { if (s == null || s.length() == 0) { return 0; } return digui(s, 0); } //递归的套路,加一个index控制递归的层次 private int digui(String s, int start) { //递归的第一步,应该是加终止条件,避免死循环。 if (s.length() == start) { ...
LeetCode 394:字符串解码 Decode String 题目: 给定一个经过编码的字符串,返回它解码后的字符串。 Given an encoded string, return its decoded string. 1.4K10 Decode String 中文给定一个经过编码的字符串,返回其解码字符串。编码规则为:k[encoded_string],其中中括号内的encoded_string被重复k次。注意k一定...
publicclassSolution{publicStringdecodeString(Strings){returndecodeSub(s,1);}publicStringdecodeSub(Stringsub,intcount){StringtrueStr="";for(inti=0;i<sub.length();i++){if(sub.charAt(i)-'1'>=0& .charAt(i)-'9'<=0){intsubCount=sub.charAt(i)-'0';while(sub.charAt(i+1)-'0'>=0& ...
leetcode/lintcode 题解] 解码字符串 · Decode String 【题目描述】 给出一个表达式 s,此表达式包括数字,字母以及方括号。在方括号前的数字...