解释错误提示 "function declaration isn't a prototype [-Werror=strict-prototypes]" 的含义 这个错误通常出现在使用GCC编译器(特别是针对C语言)时,且启用了-Werror=strict-prototypes选项。这个选项将strict-prototypes警告提升为错误,要求所有的函数声明都必须包含完整的原型,即函数声明时必须明确指定函数的返回类型和...
error:functiondeclarationisn’taprototype[-Werror=strict-prototypes]uint32_tsysctl_get_p() 原因:之前用的arm4.4.3编译链没报错,后面用的gcc-linaro6.5.0报错,看来是不同编译链的规则导致。函数无参数,不能空着,需要加void: uint32_t sysctl_get_p(void)...
function declaration isn't a prototype解决办法,对以上程序,在编译驱动的时候会出现以下warning:在网上查到解决办法是:即使函数括号内没有任何参数,也要加一个void类型,来避免这种warning:解决如下:
所以：你的编译出现的问题可能是编译器的问题。或者程序放在有汉字写的文件夹里了。重新安装WINAVR和AVRSTUDIO，重新编译。
function declaration isn't a prototype解决办法 解决办法是:即使函数括号内没有任何参数,也要加一个void类型,来避免这种warning。
Q: function declaration isn't a prototype A: http://hi.baidu.com/%D4%BC%D0%DE%D1%C7ing/blog/item/d5f86a0f598b47c27acbe138.html static void cut_mode(void) 如果写成static void cut_mode() 就会有警告function declaration isn't a prototype...
"warning: function declaration isn't a prototype" was caused by the function like that: return_type XXX() { ... } Please just modify the input paramter to void.return_type XXX(void) { ... } Or turn off the warning with -Wno-strict-prototypes (or simply by omitting -Wstrict-prototype...
warning: function declaration isn’t a prototype(函数声明不是原型)的解决办法,linux驱动中定义一个无参的函数intprobe_num(){ ...}警告:函数声明不是一个原型[-Ws
declaration isn't a prototype [-Werror=strict-prototypes] RETCODE SQL_API TraceCloseLogFile(); /* Request to close a trace log / ^~~~ /dbms/DB2/9.7/LINUX3.10/include/sqlext.h:2134:1: error: function declaration isn't a prototype [-Werror=strict-prototypes] DWORD SQL_API TraceVersion...
./ir.c:45: warning: function declaration isn't a prototype 虽然不是error,但总不顺眼.应该如何...