In fact, cot(θ) can be expressed in terms of csc(θ) and sec(θ) (secant, which is 1/cos(θ)), but a more direct relationship is cot(θ) = cos(θ) / sin(θ). Alternatively, we can say that both csc(θ) and cot(θ) are functions of sin(θ) and cos(θ), and they ar...
From one of the Pythagorean identities, csc2θ - cot2θ = 1. From this, we get cot2θ = csc2θ - 1. If we take square root on both sides, cot θ = √(csc2θ - 1). Therefore, cot in terms of csc is, cot θ = √(csc2θ - 1)...
( ((cos)(-t))/((sin)(-t))⋅ 1/((cos)(-t))) Cancel the common factor of ( (cos)(-t)). ( 1/((sin)(-t))) Convert from ( 1/((sin)(-t))) to ( (csc)(-t)). ( (csc)(-t)) 反馈 收藏
csc x over cot x - cot x over 1 + csc x; tan x Find the identity \frac{\cos(x - y)}{(\sin x \sin y)} = \cot x \cot y + 1. Rewrite the following expression in terms of the given function: cot x / tan x + cot x; sec x Write the given expression in algebraic ...
How do you verify sin(x) + cos(x) cot(x) = csc(x)? Using the formulas of trigonometric identities to verify a basic trigonometric function: In trigonometry, there are six basic trigonometric functions in which it became the basis of the trigonometric identities. Therefore, through manipulation...
We can also write csc sec cot formulas in terms of sin cos tan as given below:csc x = 1/sin x sec x = 1/cos x cot x = 1/tan xDomain and Range of Cosecant, Secant, and Cotangent FunctionsCsc x is defined for all real numbers except for values where sin x is equal to zero...
Rewrite intermsofsinesandcosines, then cancel thecommon factors. Tap for more steps... Rewritecot(x)sin(x)inofand. cot(x)cos(x)+cos(x)sin(x)sin(x) cot(x)cos(x)+cos(x) cot(x)cos(x)+cos(x)cot(x)cos(x)+cos(x) cot(x)(1sec(x)+1csc(x))cot(x)(1sec(x)+1csc...
How is the cot function related to the sine and cosine functions? Answer: Cot can be expressed in terms of sine and cosine as cot(x) = cos(x)/sin(x). What is the derivative of cot(x)? Answer: The derivative of cot(x) with respect to x is equal to -csc²(x). ...
Part i: Prove thatcot2A+cot4A=csc4A−csc2A Step 1: Start with the left-hand side (LHS) LHS=cot2A+cot4A Step 2: Factor outcot2A LHS=cot2A(1+cot2A) Step 3: Use the identity1+cot2A=csc2A LHS=cot2A⋅csc2A Step 4: Substitutecot2Ain terms ofcsc2A ...
Answer to: Verify the identity: \csc x -\sin x = \cos x \cot x. By signing up, you'll get thousands of step-by-step solutions to your homework...