Answer to: Prove that the derivative of csc(x) is -csc(x)cot(x) (i.e. f(x) = csc(x) \to f'(x) = -csc(x)cot(x)). By signing up, you'll get thousands...
Find the derivative of the function. y = csc(cotx)Differentiation:Consider a function y=f(x) then differentiation is given bydydx=f′(x) Derivative of cscx is ddxcscx=−cscxcotx Derivative of cotx is ddxcotx=−csc2x ...
The derivative of cot xThe derivative of sec xThe derivative of csc xTHE DERIVATIVE of sin x is cos x. To prove that, we will use the following identity:sin A − sin B = 2 cos ½(A + B) sin ½(A − B).(Topic 20 of Trigonometry.)...
What is the derivative of cot 1? First, the derivative of cot x is - csc^2 x. The derivative of cot 1 is, therefore, - csc^2 1. How do you find the derivative of COTX? To find the derivative of cot x, start by writing cot x = cos x/sin x. Then, apply the quotient rule...
Answer to: Find the derivative of csc x By signing up, you'll get thousands of step-by-step solutions to your homework questions. You can also ask...
Derivative of cos(kt) 3 Derivative of sec(kt) 4 Anti of csc(kt)cot(kt) 不知道嗎? 本學習集中的詞語(23) Derivative of e^kt ke^kt Derivative of ln(t) 1/t Derivative of k^t ln(k)*k^t Derivative of sin(kt) kcos(kt) Derivative of cos(kt) -ksin(kt) Derivative of tan(kt)...
Find the derivative off(x)=x+1x. View Solution Find the second order derivative off(x)=2cosx+xwith respect to x View Solution View Solution Find the derivative of sinxcosx=x+y with respect to x View Solution Find the derivative of(1+cosx)xwith respect to x. ...
( 3d/(dn)[(cot)(nx)]) Differentiate using the chain rule, which states that ( d/(dn)[f(g(n))]) is ( f()' (g(n))g()' (n)) where ( f(n)=(cot)(n)) and ( g(n)=nx). ( 3(-((csc))^2(nx)d/(dn)[nx])) Differentiate. ( -3x((csc))^2(nx)) 反馈...
•csc(x)—cosecant •arcsec(x)—arcsecant •arccsc(x)—arccosecant •arsech(x)—inverse hyperbolic secant •arcsch(x)—inverse hyperbolic cosecant •|x|,abs(x)—absolute value •sqrt(x),root(x)—square root •exp(x)—e to the power of x ...
Next, we need to find the derivative of cotx:ddx(cotx)=−csc2xSubstituting this back into our equation gives:dydx=−1√1−cot2x⋅(−csc2x)This simplifies to:dydx=csc2x√1−cot2x Step 4: Simplify the expressionNow, we need to simplify √1−cot2x. We know that:1−cot2x=...