cos4x=cos4x+4cos2x+38 cos5x=cos5x+5cos3x+10cosx16 cos6x=cos6x+6cos4x+15cos2x+1032 cos7x=cos7x+7cos5x+21cos3x+35cosx64 cos8x=cos8x+8cos6x+28cos4x+56cos2x+35128 cos9x=cos9x+9cos7x+36cos5x+84cos3x+126cosx256 ⋮ cos2nx=∑m=0n−1C2nmcos2(n−m)x22n−1+C2nn4n ...
数学函数图像为您作cosx-cos(3x)+cos(5x)-cos(7x)的函数图像。
【题目】化简sinxcosx+cos3x+cos5x+cos7x 相关知识点: 试题来源: 解析 【解析】 sinxcosx+cos3x+cosx+cosx+cosx=sinxcos5x+sinxcos3x+sinxcos7x =1/2[sin2x+sin4x+sin(-2x)+sin[π/(2)x+sinx]+sin(-4x)+sin[π/(2)x+π/(2)x+ =1/2sin8x ...
数学函数图像为您作cosx-cos(3x)-cos(5x)+cos(7x)+ cos(9x)+cos(11x)的函数图像。
cosx+cos3x+cos5x+cos7xcosxcos2xcos4x. 相关知识点: 试题来源: 解析 4. 结果一 题目 求极限 答案 结果二 题目 (3)lim_(x→0)(cos2x-cos3x)/(x^2)长干 答案 解:原式=lim_(x→0)(-2sin2x+3sin3x)/(2x) =lim_(x≥0)(-4cm^2x+9cosx)/2 =5/2相关推荐 1求极限 2(3)lim_(x→0...
∫cosx(cos^2)3xdx =(1/2)∫cosx(1+cos6x)dx =(1/2)sinx+(1/4)∫(cos7x+cos5x)dx =(1/2)sinx+(1/28)∫(cos7x)d(7x)+(1/20)∫(cos5x)d(5x)=(1/2)sinx+(1/28)sin7x+(1/20)sin5x+C 你上面写的∫cosx(cos^2)3xdx中间部分写的不是很明确，我按照 (cos3x)^2 ...
先积化和差 1/2(cos3x+cosx)=1/2(cos7x+cosx)即cos3x-cos7x=0 再和差化积 2sin2xsin5x=0 即x=kπ/2或x=kπ/5
∫cosx(cos^2)3xdx =∫cosx*(1+cos6x)/2dx =1/2∫cosxdx+1/2∫cosxcos6xdx =1/2 *sinx+1/2∫cosxcos6xdx =1/2 *sinx+1/2∫[cos(x+6x)+cos(x-6x)]/2dx =1/2 *sinx+1/4∫[cos7x+cos5x]dx =1/2*sinx+1/20*sin5x+1/28*sin7x+C ...
2sin(x/2)[cosx+cos2x+cos3x+……+cosnx ]=2sin(x/2)cosx+2sin(x/2)cos2x+2sin(x/2)cos3x+……+2sin(x/2)cosnx =sin(3x/2)-sin(x/2)+sin(5x/2)-sin(3x/2)+sin(7x/2)-sin(5x/2)+……+sin(x/2+nx)-sin(nx-x/2)=sin(x/2+nx)-sin(x/2)所以，cosx+cos2x+...
Tinh cá c tich phàn sau1. ∫cos5xcos7xdx ; 2. fsin6xcos2xdx,3.∫cosxcosx/2cosx/4dx .2