Can you solve this real interview question? Coin Change - You are given an integer array coins representing coins of different denominations and an integer amount representing a total amount of money. Return the fewest number of coins that you need to m
https://leetcode-cn.com/problems/coin-change 解题思路 动态规划,自底向上,太简单,不解释。 C++代码 classSolution{public:intcoinChange(vector<int>& coins,intamount){vector<int>dp(amount +1, amount +1); dp[0] =0;for(inti =1; i <= amount; i++) {for(autov : coins) {if(i >= v)...
【leetcode】322. Coin Change 题目: You are given coins of different denominations and a total amount of money amount. Write a function to compute the fewest number of coins that you need to make up that amount. If that amount of mo......
[LeetCode] Coin Change Coin Change You are given coins of different denominations and a total amount of moneyamount. Write a function to compute the fewest number of coins that you need to make up that amount. If that amount of money cannot be made up by any combination of the coins, ...
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LeetCode: 322. Coin Change 题目描述 You are given coins of different denominations and a total amount of money amount. Write a function to compute the fewest number of coins that you need to make up that amount. If that amount of money cannot be made up by any combination of the coins...
代码(Python3) class Solution: def coinChange(self, coins: List[int], amount: int) -> int: # dp[i] 表示凑出 i 所需的最少硬币数量, # 初始化为 amount + 1 ,表示当前还凑不出 dp: List[int] = [amount + 1] * (amount + 1) # 最开始只能确认不需要任何硬币就可以凑出 0 dp[0] ...
// solve 5 : dfs + greedy + pruning var coinChange = function(coins,amount){ var res = Infinity coins.sort((a,b)=>b-a) change(amount,0,0) return res === Infinity?-1:res // 内部调用函数类 function change(amount,count,cidx){ // base case if(amount === 0){ res = Math.mi...