代码如下: classSolution(object):defchange(self, amount, coins):""" :type amount: int :type coins: List[int] :rtype: int """dp = [0] * (amount +1) dp[0] =1forcoinincoins:foriinrange(1, amount +1):ifcoin <= i: dp[i] += dp[i - coin]returndp[amount]classSolution(objec...
1classSolution {2publicintchange(intamount,int[] coins) {3if(amount < 0 || coins ==null){4return0;5}67int[] dp =newint[amount + 1];8dp[0] = 1;910for(intcoin : coins){11for(inti = 1; i <= amount; i++){12if(i - coin < 0){13continue;14}1516dp[i] += dp[i -co...
Can you solve this real interview question? Coin Change - You are given an integer array coins representing coins of different denominations and an integer amount representing a total amount of money. Return the fewest number of coins that you need to m
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322 Coin Change 零钱兑换 Description: You are given coins of different denominations and a total amount of money amount. Write a function to compute the fewest number of coins that you need to make up that amount. If that amount of money cannot be made up by any combination of the coins...
Leetcode 322. Coin Change noahsnail.com|CSDN|简书 1. Description Coin Change 2. Solution Version 1 classSolution:defcoinChange(self, coins, amount):ifamount ==0:return0stat = [0] * (amount +1)foriinrange(amount +1):forcoinincoins:ifi - coin >0andstat[i - coin] >0:ifstat[i] ...
first one. There exists a solution for sum 2 (3 - 1) and therefore we can construct from it a solution for sum 3 by adding the first coin to it. Because the best solution for sum 2 that we found has 2 coins, the new solution for sum 3 will have 3 coins. Now let's take the...
* Example 2: * coins = [2], amount = 3 * return -1. * <p> * Note: * You may assume that you have an infinite number of each kind of coin. * * @author zhangxu * @see https://leetcode.com/problems/coin-change/ * @see net.neoremind.mycode.argorithm.dp.C...
// solve 5 : dfs + greedy + pruning var coinChange = function(coins,amount){ var res = Infinity coins.sort((a,b)=>b-a) change(amount,0,0) return res === Infinity?-1:res // 内部调用函数类 function change(amount,count,cidx){ // base case if(amount === 0){ res = Math.mi...
leetcode的testcase有一个为amount为0的时候,所以在代码的开头加了一个判断。 吐槽一下leetcode怎么有这么多诡异的testcase。 classSolution:defcoinChange(self,coins:List[int],amount:int)->int:ifamount==0:return0dp=[amount+1]*(amount+1)dp[0]=0foriinrange(1,amount+1):forcincoins:ifi>=c:dp...