privateintres = Integer.MAX_VALUE; publicintcoinChange(int[] coins,intamount) { Arrays.sort(coins); coinChange(coins, amount, coins.length-1,0); returnres==Integer.MAX_VALUE ? -1: res; } // privatevoidcoinChange(int[] coins,intamount,intcur,intcount) { if(cur <0) return;// stop...
https://leetcode-cn.com/problems/coin-change 解题思路 动态规划,自底向上,太简单,不解释。 C++代码 classSolution{public:intcoinChange(vector<int>& coins,intamount){vector<int>dp(amount +1, amount +1); dp[0] =0;for(inti =1; i <= amount; i++) {for(autov : coins) {if(i >= v)...
Can you solve this real interview question? Coin Change - You are given an integer array coins representing coins of different denominations and an integer amount representing a total amount of money. Return the fewest number of coins that you need to m
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LeetCode: 322. Coin Change LeetCode: 322. Coin Change 题目描述 You are given coins of different denominations and a total amount of money amount. Write a function to compute the fewest number of coins that you need to make up that amount. If that amount of money cannot be made up by ...
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}returndp[amount] = cur == INT_MAX ? -1: cur; } }; 本文转自博客园Grandyang的博客,原文链接:硬币找零[LeetCode] Coin Change,如需转载请自行联系原博主。
LeetCode 322. Coin Change You are given coins of different denominations and a total amount of money amount. Write a function to compute the fewest number of coins that you need to make up that amount. If that amount of money ......
// solve 5 : dfs + greedy + pruning var coinChange = function(coins,amount){ var res = Infinity coins.sort((a,b)=>b-a) change(amount,0,0) return res === Infinity?-1:res // 内部调用函数类 function change(amount,count,cidx){ // base case if(amount === 0){ res = Math.mi...
Leetcode 322. Coin Change 硬币找零问题 MaRin 菜鸡一只 给你一个整数数组 coins ,表示不同面额的硬币;以及一个整数 amount ,表示总金额。计算并返回可以凑成总金额所需的 最少的硬币个数 。如果没有任何一种硬币组合能组成总金额,返回 -1 。你可以认为每种硬币的数量是无限的。对应leetcode链接为: https:/...