(参考视频讲解:Leetcode力扣|206反转链表|递归|reverse linked list_哔哩哔哩_bilibili) # 定义一个链表节点类classListNode:def__init__(self,val=0,next=None):# 初始化函数self.val=val# 节点的值self.next=next# 指向下一个节点的指针# 将给出的数组转换为链表deflinkedlist(list):head=ListNode(list[0]...
1#Definition for singly-linked list.2#class ListNode:3#def __init__(self, x):4#self.val = x5#self.next = None67classSolution:8#@param head, a ListNode9#@param m, an integer10#@param n, an integer11#@return a ListNode12defreverseBetween(self, head, m, n):13ifheadisNoneorhead....
空间复杂度:O(1) Python3代码 # Definition for singly-linked list.# class ListNode:# def __init__(self, x):# self.val = x# self.next = NoneclassSolution:defreverseList(self, head: ListNode) -> ListNode:# solution three: recursionifnotheadornothead.next:returnhead pos = head.nextnewL...
代码(Python3) # Definition for singly-linked list. # class ListNode: # def __init__(self, val=0, next=None): # self.val = val # self.next = next class Solution: def reverseBetween(self, head: Optional[ListNode], left: int, right: int) -> Optional[ListNode]: # 定义一个哨兵结点...
def reverseList(self, head): """ :type head: ListNode :rtype: ListNode """ dummy = ListNode(None) while head: # 终止条件是head=Null nextnode = head.next # nextnode是head后面的节点 head.next = dummy # dummy.next是Null,所以这样head.next就成为了Null ...
publicclassSolution{publicListNodereverseBetween(ListNode head,int m,int n){if(m==n||head==null||head.next==null){returnhead;}ListNode pre=newListNode(0);pre.next=head;ListNode Mpre=pre;ListNode NodeM=head;ListNode NodeN=head;int mNum=1;int nNum=1;while(mNum<m&&NodeM!=null){Mpre=...
next, dummy.next else: return False return True def reverse(self, node): prev = None while node: tmp = node.next node.next = prev prev = node node = tmp return prev # prev <- node(None) Python Copy 最近在練習程式碼本身就可以自解釋的 Coding style,可以嘗試直接閱讀程式碼理解...
2612.Minimum-Reverse-Operations (H) 2736.Maximum-Sum-Queries (H) Dual Multiset 295.Find-Median-from-Data-Stream (M) 1825.Finding-MK-Average (H) 2653.Sliding-Subarray-Beauty (M+) 3013.Divide-an-Array-Into-Subarrays-With-Minimum-Cost-II (H-) Maintain intervals 715.Range-Module (H) 2213...
2. A palindrome can be expanded from its center 3. Manacher algorithm 7Reverse IntegerPythonJavaOverflow when the result is greater than 2147483647 or less than -2147483648. 8String to Integer (atoi)PythonJavaOverflow, Space, and negative number ...
{I will also make you a light for the Gentiles,} \rightline{that my salvation may reach to the ends of the earth.} \smallskip \rightline{Isaiah 49:6} %CEP }\eject The \OpBible/ macro collection may be freely copied, distributed and used in accordance with GNU General Public License ...