1#Definition for singly-linked list.2#class ListNode:3#def __init__(self, x):4#self.val = x5#self.next = None67classSolution:8#@param head, a ListNode9#@param m, an integer10#@param n, an integer11#@return a ListNode12defreverseBetween(self, head, m, n):13ifheadisNoneorhead....
王几行xing:【Python-转码刷题】LeetCode 203 移除链表元素 Remove Linked List Elements 提到翻转,熟悉Python的朋友可能马上就想到了列表的 reverse。 1. 读题 2. Python 中的 reverse 方法 list1 = list("abcde") list1.reverse() list1 [Out: ] ['e', 'd', 'c', 'b', 'a'] 2.1 reverse 在...
第一种方法:迭代 代码语言:javascript 代码运行次数:0 classListNode(object):def__init__(self,x):self.val=x self.next=NoneclassSolution(object):defreverseList(self,head):""":type head:ListNode:rtype:ListNode""" pre=cur=Noneifhead:pre=head cur=head.next pre.next=Noneelse:returnNonewhilecur:...
# Definition for singly-linked list.# class ListNode:# def __init__(self, x):# self.val = x# self.next = NoneclassSolution:defreverseList(self, head: ListNode) -> ListNode:# solution one: Listpos = head newList = []whilepos: newList.insert(0, pos.val) pos = pos.nextpos = h...
代码(Python3) # Definition for singly-linked list. # class ListNode: # def __init__(self, val=0, next=None): # self.val = val # self.next = next class Solution: def reverseBetween(self, head: Optional[ListNode], left: int, right: int) -> Optional[ListNode]: # 定义一个哨兵结点...
def reverseList(self, head): """ :type head: ListNode :rtype: ListNode """ dummy = ListNode(None) while head: # 终止条件是head=Null nextnode = head.next # nextnode是head后面的节点 head.next = dummy # dummy.next是Null,所以这样head.next就成为了Null ...
p = self.reverseList(head.next) # 因为经上已经反转head.next部分,此时next链表部分的最后一个节点就是head.next, # head.next节点指向head,即完成单次递归右往左的反转 head.next.next = head # 由于head指针为当前递归的最后一个元素,next指向空即可 ...
Reverse Linked List II 题目大意 翻转指定位置的链表 解题思路 将中间的执行翻转,再将前后接上 代码 迭代 代码语言:javascript 代码运行次数:0 运行 AI代码解释 classSolution(object):# 迭代 defreverseBetween(self,head,m,n):""":type head:ListNode:type m:int:type n:int:rtype:ListNode""" ...
next, dummy.next else: return False return True def reverse(self, node): prev = None while node: tmp = node.next node.next = prev prev = node node = tmp return prev # prev <- node(None) Python Copy 最近在練習程式碼本身就可以自解釋的 Coding style,可以嘗試直接閱讀程式碼理解...
2612.Minimum-Reverse-Operations (H) 2736.Maximum-Sum-Queries (H) Dual Multiset 295.Find-Median-from-Data-Stream (M) 1825.Finding-MK-Average (H) 2653.Sliding-Subarray-Beauty (M+) 3013.Divide-an-Array-Into-Subarrays-With-Minimum-Cost-II (H-) Maintain intervals 715.Range-Module (H) 2213...