# Definition for singly-linked list.# class ListNode: # def __init__(self, val=0, next=None): # self.val = val # self.next = next class Solution: ''' # 递归 def reverseList(self, head: Optional[ListNode]) -> Op
# Definition for singly-linked list. # class ListNode: # def __init__(self, val=0, next=None): # self.val = val # self.next = next class Solution: def reverseBetween(self, head: Optional[ListNode], left: int, right: int) -> Optional[ListNode]: i = 0 p = head p_l = None...
代码:oj测试通过 Runtime: 65 ms 1#Definition for singly-linked list.2#class ListNode:3#def __init__(self, x):4#self.val = x5#self.next = None67classSolution:8#@param head, a ListNode9#@param m, an integer10#@param n, an integer11#@return a ListNode12defreverseBetween(self, head...
def reverse_linked_list(head): prev = None curr = head while curr: next_node = curr.next curr.next = prev prev = curr curr = next_node return prev # 测试 node1 = ListNode(1) node2 = ListNode(2) node3 = ListNode(3) node1.next = node2 node2.next = node3 reversed_head = re...
Reverse Linked List II 题目大意 翻转指定位置的链表 解题思路 将中间的执行翻转,再将前后接上 代码 迭代 代码语言:javascript 代码运行次数:0 运行 AI代码解释 classSolution(object):# 迭代 defreverseBetween(self,head,m,n):""":type head:ListNode:type m:int:type n:int:rtype:ListNode""" ...
Reverse a singly linked list. Example: Input:1->2->3->4->5->NULL Output:5->4->3->2->1->NULL Follow up: A linked list can be reversed either iteratively or recursively. Could you implement both? 问题 力扣 反转一个单链表。
Reverse Linked List 反转单链表。 Description iterative: # Definition for singly-linked list. # class ListNode(object): # def __init__(self, x): # self.val = x # self.next = None class Solution(object): def reverseList(self, head): """ :type head: ListNode :rtype: ListNode ""...
Reverse Linked List II 题目: Reverse a linked list from position m to n. Do it in one-pass. Note: 1 ≤ m ≤ n ≤ length of list. Example: Input: 1->2->3->4->5->NULL, m = 2, n = 4 Output: 1->4->3->...
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