应该写为把dummy都替换成dummy.next: class Solution(object): # 迭代 def reverseList(self, head): """ :type head: ListNode :rtype: ListNode """ dummy = ListNode(None) while head: # 终止条件是head=Null nextnode = head.next # nextnode是head后面的节点(保持下个节点信息不丢) head.next =...
(参考视频讲解:Leetcode力扣|206反转链表|递归|reverse linked list_哔哩哔哩_bilibili) # 定义一个链表节点类classListNode:def__init__(self,val=0,next=None):# 初始化函数self.val=val# 节点的值self.next=next# 指向下一个节点的指针# 将给出的数组转换为链表deflinkedlist(list):head=ListNode(list[0]...
https://leetcode-cn.com/problems/reverse-linked-list/solution/shi-pin-jiang-jie-die-dai-he-di-gui-hen-hswxy/ python # 反转单链表 迭代或递归 class ListNode: def __init__(self, val): self.val = val self.head = None class Solution: def reverseList2(self, head: ListNode) -> ListNode...
# Definition for singly-linked list.# class ListNode:# def __init__(self, x):# self.val = x# self.next = NoneclassSolution:defreverseList(self, head: ListNode) -> ListNode:# solution three: recursionifnotheadornothead.next:returnhead pos = head.nextnewList = self.reverseList(pos) h...
【leetcode python】206. Reverse Linked List # Definition for singly-linked list. # class ListNode(object): # def __init__(self, x): # self.val = x # self.next = None class Solution(object): def reverseList(self, head): if(head==None):return None...
Python3代码 # Definition for singly-linked list.# class ListNode:# def __init__(self, x):# self.val = x# self.next = NoneclassSolution:defreverseList(self,head:ListNode)->ListNode:# solution one: Listpos=head newList=[]whilepos:newList.insert(0,pos.val)pos=pos.nextpos=headfor_in...
LeetCode 206. 反转链表(Reverse Linked List) 示例: 输入:1->2->3->4->5->NULL输出:5->4->3->2->1->NULL 切题 一、Clarification 只需注意为空链表的情况 二、Possible Solution 1、迭代 2、递归 可利用哨兵简化实现难度 Python3 实现
Leetcode 92题反转链表 II(Reverse Linked List II) LeetCode 206题 反转链表(Reverse Linked List) 题目链接 https://leetcode-cn.com/problems/reverse-linked-list-ii/ 题目描述 反转从位置 m 到 n 的链表。请使用一趟扫描完成反转。 说明: 1 ≤ m ≤ n ≤ 链表长度。 示例: 输入: 1->2->3->4-...
Explore - LeetCodeleetcode.com/explore/interview/card/top-interview-questions-easy/93/linked-list/560/ Solutions: 1. Iterative method: The idea of this method is just to reverse the direction of the link one by one. And because you are reversing the direction, in order to get to the...
92. 反转链表 II - 给你单链表的头指针 head 和两个整数 left 和 right ,其中 left <= right 。请你反转从位置 left 到位置 right 的链表节点,返回 反转后的链表 。 示例 1: [https://assets.leetcode.com/uploads/2021/02/19/rev2ex2.jpg] 输入:head = [1,2,3,4