classSolution:defmaxProfit(self,prices:List[int])->int:## 双指针解法left,right=0,1# left=buy, right=sellmaxP=0whileright<len(prices):## 遍历整个 listifprices[right]>prices[left]:## 在存在赚钱机会的条件下profit=prices[right]-prices[left]maxP=max(maxP,profit)else:## 对于任意一个右指...
【leetcode】43-best-time-to-buy-and-sell-stock-iv 力扣 188. 买卖股票的最佳时机 IV 【leetcode】44-best-time-to-buy-and-sell-stock-with-cooldown 力扣 309. 买卖股票的最佳时机包含冷冻期 【leetcode】45-best-time-to-buy-and-sell-stock-with-cooldown 力扣 714. 买卖股票的最佳时机包含手续费 ...
buy = Math.max(sell - prices[i], pre_buy); sell = Math.max(pre_buy + prices[i], sell); } return sell; } 1. 2. 3. 4. 5. 6. 7. 8. 9. 10. 11. 第三题:https://leetcode.com/problems/best-time-to-buy-and-sell-stock-with-cooldown/?tab=Description 在第...
1 int maxProfit(vector<int>& prices) { 2 int min = prices[0]; 3 int maxProfile = 0; 4 for(int j = 1;j < prices.size();++j) 5 { 6 if(prices[j] < min) 7 min = prices[j]; 8 else 9 maxProfile = max(maxProfile , prices[j] - min); 10 } 11 return maxProfile; 12...
leetcode122 Best Time to Buy and Sell Stock 题意:有一个数组,第i个数据代表的是第i天股票的价格,每天只能先卖出再买进(可以不卖出也可以不买进),求最大收益。 思路:自己去弄几个数组比划比划就知道了,比如[1,2,5,3,6],第一天买进,第二天卖出,再买进,第三天卖出,第四天买进,第五天卖出。
Can you solve this real interview question? Best Time to Buy and Sell Stock - You are given an array prices where prices[i] is the price of a given stock on the ith day. You want to maximize your profit by choosing a single day to buy one stock and choo
[leetcode] 121. Best Time to Buy and Sell Stock Description Say you have an array for which the ith element is the price of a given stock on day i. If you were only permitted to complete at most one transaction (i.e., buy one and sell one share of the stock), design an ...
Can you solve this real interview question? Best Time to Buy and Sell Stock III - You are given an array prices where prices[i] is the price of a given stock on the ith day. Find the maximum profit you can achieve. You may complete at most two transacti
Best Time to Buy and Sell Stock IV中是求某个给定k次交易的最大收益,和Maximum Subarray III完全一样 本题由于是可以操作任意次数,只为获得最大收益,而且对于一个上升子序列,比如:[5, 1, 2, 3, 4]中的1, 2, 3, 4序列来说,对于两种操作方案: 1 在1买入,4卖出 2 在1买入,2卖出同时买入,3卖出...
Best Time to Buy and Sell Stock II class Solution(object): def maxProfit(self, prices): """ :type prices: List[int] :rtype: int """ return sum(max(prices[i+1]-prices[i],0) for i in range(len(prices)-1)) 解题思路:只要第二天的价格比前一天高,就买了再卖...