classSolution:defmaxProfit(self,prices:List[int])->int:## 双指针解法left,right=0,1# left=buy, right=sellmaxP=0whileright<len(prices):## 遍历整个 listifprices[right]>prices[left]:## 在存在赚钱机会的条件下profit=prices[right]-prices[left]maxP=max(maxP,profit)else:## 对于任意一个右指...
【leetcode】43-best-time-to-buy-and-sell-stock-iv 力扣 188. 买卖股票的最佳时机 IV 【leetcode】44-best-time-to-buy-and-sell-stock-with-cooldown 力扣 309. 买卖股票的最佳时机包含冷冻期 【leetcode】45-best-time-to-buy-and-sell-stock-with-cooldown 力扣 714. 买卖股票的最佳时机包含手续费 ...
在计算第一个时,因为sell之前没有buy因此只能从第一个元素开始,buy的第一个设置为-prices[0],sell和presell设置为0,这样就可以计算第一个元素的buy。 另外还有一道比较类似的robber题目:https://leetcode.com/problems/house-robber/?tab=Description。思路还是应用一个序列,只不过stock里面要考虑以...
这题算的是最大利润,原先我想的是找到最小值和最大值,之差不就是最大利润了么,后来想想,最小值可能在最大值之后,不能说在3号买进了回去1号卖出股票哈~然后想,记录某天之前的最小值,再记录那天之后的最大值,这么一算就能算出在某段时间内的最大利润了,再比一比好几段时间内的利润,就能算出最终的最...
classSolution{public:intmaxProfit(vector<int>& prices){intsell =0;intbuy =0;if(prices.empty()){return0; }else{ buy = -prices[0]; }for(intprice : prices){ sell =max(sell, buy + price); buy =max(buy, -price); }returnsell; ...
https://leetcode.com/problems/best-time-to-buy-and-sell-stock-ii/ 因为可以进行无限次交易,并且在下一次buy之前必须已经sell。所以只需要把所有price曲线价格上涨的部分加起来就行。 class Solution(object): def maxProfit(self, prices): """
Can you solve this real interview question? Best Time to Buy and Sell Stock - You are given an array prices where prices[i] is the price of a given stock on the ith day. You want to maximize your profit by choosing a single day to buy one stock and choo
Can you solve this real interview question? Best Time to Buy and Sell Stock III - You are given an array prices where prices[i] is the price of a given stock on the ith day. Find the maximum profit you can achieve. You may complete at most two transacti
LeetCode 0121. Best Time to Buy and Sell Stock买卖股票的最佳时机【Easy】【Python】【贪心】 Problem LeetCode Say you have an array for which theith element is the price of a given stock on dayi. If you were only permitted to complete at most one transaction (i.e., buy one and sell...
【leetcode】45-best-time-to-buy-and-sell-stock-with-cooldown 力扣 714. 买卖股票的最佳时机包含手续费 开源地址 为了便于大家学习,所有实现均已开源。欢迎 fork + star~ https://github.com/houbb/leetcode 122. 买卖股票的最佳时机 II 给你一个整数数组 prices ,其中 prices[i] 表示某支股票第 i 天...