link:[https://leetcode.com/explore/learn/card/data-structure-tree/134/traverse-a-tree/928/] 递归解法: #Definition for a binary tree node.#class TreeNode(object):#def __init__(self, x):#self.val = x#self.left = None#self.right = NoneclassSolution(object):defsolve(self,root):ifroo...
1 struct TreeNode { 2 int val; 3 TreeNode* left; 4 TreeNode* right; 5 TreeNode(int x): val(x), left(NULL),right(NULL) {} 6 }; 7 8 void Swap(vector<int> &ivec) 9 { 10 int temp = 0; 11 int len = ivec.size(); 12 for (int i = 0; i < len/2; i ++) { 13...
* ele in aiArr is different.*/structTreeNode* initBinaryTree(intaiArr[],intiSize) {structTreeNode *pstNode =NULL;structTreeNode *pstLeft =NULL;structTreeNode *pstRight =NULL;structTreeNode *pstRoot =NULL;inti =0;for(; i < iSize; i++) {if(0==i) {/*as root*/if(!aiArr[0])...
Left != nil || root.Right != nil { return root } // 此时当前子树中的所有子结点都是 0 ,需要修剪掉 return nil } 题目链接: Binary Tree Pruning: leetcode.com/problems/b 二叉树剪枝: leetcode.cn/problems/bi LeetCode 日更第 235 天,感谢阅读至此的你 欢迎点赞、收藏鼓励支持小满...
Given a binary tree, return the level order traversal of its nodes' values. (ie, from left to right, level by level). For example: Given binary tree [3,9,20,null,null,15,7], 代码语言:javascript 代码运行次数:0 运行 AI代码解释 ...
LeetCode 105. Construct Binary Tree from Preorder and Inorder Traversal Description Given preorder and inorder traversal of a tree, construct the binary tree. Note: You may assume that duplicates do not exist in the tree. For example, given ...
Given a binary tree, find its minimum depth. The minimum depth is the number of nodes along the shortest path from the root node down to the nearest leaf node. Note: A leaf is a node with no children. Example 1: Input: root = [3,9,20,null,null,15,7] Output: 2 Example 2: ...
Can you solve this real interview question? Minimum Depth of Binary Tree - Given a binary tree, find its minimum depth. The minimum depth is the number of nodes along the shortest path from the root node down to the nearest leaf node. Note: A leaf is a
简单 95. 不同的二叉搜索树 II 74.6% 中等 96. 不同的二叉搜索树 71.5% 中等 98. 验证二叉搜索树 39.3% 中等 99. 恢复二叉搜索树 61.3% 中等 100. 相同的树 63.2% 简单 101. 对称二叉树 62.3% 简单 102. 二叉树的层序遍历 69.7% 中等 103. 二叉树的锯齿形层序遍历 60.2% 中等 104. 二叉树的最大...
968. 监控二叉树 - 给定一个二叉树,我们在树的节点上安装摄像头。 节点上的每个摄影头都可以监视其父对象、自身及其直接子对象。 计算监控树的所有节点所需的最小摄像头数量。 示例 1: [https://assets.leetcode-cn.com/aliyun-lc-upload/uploads/2018/12/29/bst_c