root.right.right =newTreeNode(7); root.right.right.right =newTreeNode(8); System.out.println(Main21.inorderTraversal(root)); } publicstaticclassTreeNode { intval; TreeNode left; TreeNode right; TreeNode(intx) { val = x; } } staticArrayList<Integer> array =newArrayList<>(); publicsta...
TreeNode rightChild;intvalue;publicTreeNode(intvalue){this.value = value; }publicTreeNode(){ } }publicstaticvoidmain(String[] args){BinaryTreeInOrderTraversalbinaryTreeInOrderTraversal=newBinaryTreeInOrderTraversal();char[] arr1 =newchar[]{'1','#','2','3'};char[] arr2 =newchar[]{'1...
Given a binary tree, return theinordertraversal of its nodes' values. For example: Given binary tree{1,#,2,3}, 1 \ 2 / 3 1. 2. 3. 4. 5. return[1,3,2]. 1 /** 2 * Definition for binary tree 3 * struct TreeNode { ...
Binary Tree Inorder Traversal Given a binary tree, return the inorder traversal of its nodes’ values. Example: Input: [1,null,2,3] 1 2 / 3 Output: [1,3,2] 题意 输出二叉树的中序遍历 思路 【思路一】 递归,最常见的做法 【思路二】 ...LeetCode-94-Binary Tree Inorder Traversal 中...
inorder 【计】 中根次序 binary a. 1.【计算机,数学】二进制的 2.【术语】仅基于两个数字的,二元的,由两部分组成的 tree n. 树,木料,树状物 vt. 赶上树 Tree 树状结构使计算机知道如何执行的机器指令。 in tree 【计】 入树 binary decimal 二-十进制的 binary multiplier 二进乘法器 decimal...
public TreeNode buildTree(int[] inorder, int[] postorder) { postEnd = postorder.length - 1; return helper(postorder, inorder, 0, inorder.length - 1); } private TreeNode helper(int[] postorder, int[] inorder, int inStart, int inEnd){ ...
Given a binary tree, return the level order traversal of its nodes' values. (ie, from left to right, level by level). For example: Given binary tree [3,9,20,null,null,15,7], 代码语言:javascript 代码运行次数:0 运行 AI代码解释 ...
3) inorder 中根次序4) right subtree in a binary tree 二叉树中的右子树5) binary sort tree 二叉排序树 1. Some investigations on that process are made and a algorithm is proposed on binary sort tree which is using for reconstructing impacted areas. 在两步法构建约束Delaunay三角网过程中,...
Leetcode 94: Binary Tree Inorder Traversal-中序遍历 自动驾驶搬砖师 一步一个台阶,一天一个脚印 一、题目描述 给定一个二叉树,返回它的中序遍历。 二、解题思路 2.1 递归法 时间复杂度 O(n) 空间复杂度 O(n) 2.2 迭代法 时间复杂度 O(n) 空间复杂度 O(n)(1) 同理创建一个Stack,然后按左/中/右...
The number of nodes in the tree is in the range [0, 100]. -100 <= Node.val <= 100 英文版地址 leetcode.com/problems/b 中文版描述 给定一个二叉树的根节点 root ,返回 它的中序 遍历。 示例1: 输入:root = [1,null,2,3] 输出:[1,3,2] 示例2: 输入:root = [] 输出:[] 示例3:...