public:intnumSubarraysWithSum(vector<int>& A,intS) {intres =0,sum=0, left =0, n = A.size();for(inti =0; i < n; ++i) {sum+= A[i];while(left < i &∑> S)sum-= A[left++];if(sum< S)continue;if(sum== S) ++res;for(intj = left; j < i && A[j] ==0; ++j)...
LeetCode 930. Binary Subarrays With Sum 原题链接在这里:https://leetcode.com/problems/binary-subarrays-with-sum/ 题目: In an arrayAof0s and1s, how many non-empty subarrays have sumS? Example 1: Input: A =[1,0,1,0,1], S =2 Output:4 Explanation: The 4 subarrays are bolded belo...
public int numSubarraysWithSum(int[] A, int S) { if (A.length == 0) return 0; int result = 0; int[] sumOne = new int[A.length]; int st = 0; int ed = 0; sumOne[0] = A[0] == 1 ? 1 : 0; for (int i = 1; i < A.length; i++) { sumOne[i] = A[i] =...
用hashmap处理即可,之前LeetCode上面有类似的题目,这次WA了一次,是put(0,0)了,应该put(0,1)的。 publicstaticintnumberOfSubarrays(int[]arr,int target){HashMap<Integer,Integer>map=newHashMap<>();int pre=0;map.put(0,1);int cnt=0;for(int i=0;i<arr.length;i++){pre+=arr[i];if(map....
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package leetcode import "math" /** * Definition for a binary tree node. * type TreeNode struct { * Val int * Left *TreeNode * Right *TreeNode * } */ // 解法一,直接按照定义比较大小,比 root 节点小的都在左边,比 root 节点大的都在右边 func isValidBST(root *TreeNode) bool { retur...
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