# Python program to check if the number provided by the user is an Armstrong number or not # take input from the user num = int(input("Enter a number: ")) # initialize sum sum = 0 # find the sum of the cube of
procedure armstrong : number check = number rem = 0 WHILE check IS NOT 0 rem ← check modulo 10 sum ← sum + (rem)3 divide check by 10 END WHILE IF sum equals to number PRINT armstrong ELSE PRINT not an armstrong END IF end procedure ...
Python program to check Armstrong number using object oriented approach# Define a class for Checking Armstrong number class Check : # Constructor def __init__(self,number) : self.num = number # define a method for checking number is Armstrong or not def isArmstrong(self) : # copy num ...
153 = 1*1*1 + 5*5*5 + 3*3*3 // 153 is an Armstrong number. Visit this page to learn how you can check whether a number is an Armstrong number or not in Python. Source Code # Program to check Armstrong numbers in a certain interval lower = 100 upper = 2000 for num in ran...
/usr/bin/python3 #-*- coding:UTF-8 -*- print("10000以内的阿姆斯特朗数有:") for number in range(1, 10001): if number < 10: #1-9都为阿姆斯特朗数,直接输出即可 print(number) elif number < 100: n1 = number % 10 #取个位数 n2 = int(number/10 % 10) #取十位数...
The program Will try with 2 numbers. Let's try 346, Now 371, It's an Armstrong Number. Cubing numbers:3*3*3 + 7*7*7 + 1= 371 (Armstrong Number) Conclusion We will go through lots of tricky logic and a simple one with Visual Studio in Python. We see it's very easy to implem...
In this Python article, you learnedHow to Find Armstrong Number Using Recursion in Pythonwith the practical example where we are taking user input to make the program dynamic. You may also like to read: Bijay Kumar I am Bijay Kumar, aMicrosoft MVPin SharePoint. Apart from SharePoint, I st...
LongestCommonPrefix.java: Write a program in Java 代写Pyramid Interests PerfectNumber ArmstrongNumbers that prompts the user to enter two stringsand display the largest common prefix of the two strings. If there are no common prefixbetween the two entered strings display a message which tells the...
Python 阿姆斯特朗数Python3 实例如果一个 n 位正整数等于其各位数字的 n 次方之和,则称该数为阿姆斯特朗数。例如 1^3 + 5^3 + 3^3 = 153。1000 以内的阿姆斯特朗数: 1, 2, 3, 4, 5, 6, 7, 8, 9, 153, 370, 371, 407。以下代码用于检测用户输入的数字是否为阿姆斯特朗数:...
printf("\nNumber %d is armstrong number", num); } } getch(); } OUTPUT: Explanation: In this program, we have to find all Armstrong numbers between 1 and 1000. For this, we firstly initialize (sum = 0) and temp = num = 1. Then we apply modulus operator(%) and various other ope...