if number < 10: #1-9都为阿姆斯特朗数,直接输出即可 print(number) elif number < 100: n1 = number % 10 #取个位数 n2 = int(number/10 % 10) #取十位数 result = n1**2 + n2**2 if number == result: print(number) elif number < 1000: n1 =
It's an Armstrong Number. Cubing numbers:3*3*3 + 7*7*7 + 1= 371 (Armstrong Number) Conclusion We will go through lots of tricky logic and a simple one with Visual Studio in Python. We see it's very easy to implement it. Read more articles onPython: Diving Into Python: Chapter 1...
Armstrong (Michael F. Armstrong) number is a number that is equal to the sum of cubes of its digits. For example 0, 1, 153, 370, 371 and 407 are the Armstrong numbers Sample Solution: Java Code: importjava.util.*;publicclasssolution{publicstaticbooleanis_Amstrong(intn){intremainder,sum=...