Suppose thenumber is 153. Then, (153 % 10 = 3 ** 3) + is_armstrong(153 // 10 = 15, 3). Here, the is_armstrong() method calls itself,so again, the same code block executes for thedigit 15and so on. This is how we
n1 = number % 10 #取个位数 n2 = int(number/10 % 10) #取十位数 result = n1**2 + n2**2 if number == result: print(number) elif number < 1000: n1 = number % 10 n2 = int(number/10 % 10) n3 = int(number/100 % 10) #取千位数 result = n1**3 + n2**3 + n3**3 if...
实例(Python 3.0+) # Filename : test.py # author by : www.runoob.com # Python 检测用户输入的数字是否为阿姆斯特朗数 # 获取用户输入的数字 num = int(input("请输入一个数字: ")) # 初始化变量 sum sum = 0 # 指数 n = len(str(num)) # 检测 temp = num while temp > 0: digit = ...
Here, we have set the lower limit 100 in variable lower and upper limit 2000 in variable upper using Python range(). We have used for loop to iterate from variable lower to upper. In iteration, the value of lower is increased by 1 and checked whether it is an Armstrong number or not...
ARMSTRONG:Yes. Well, that’s definitely true as a cultural thing. I would agree with that. There is something really important — you want the engineers to outnumber the lawyers. One of the metrics that we track inside the company is the percentage of engineering. ...
(requires device property below) and 'cpu'.type:edgetpu#Optional: device name as defined here: https://coral.ai/docs/edgetpu/multiple-edgetpu/#using-the-tensorflow-lite-python-apidevice:usb#Required: mqtt configurationmqtt:#Required: host namehost:mqtt.server.com#Optional: port (default: ...
vim.textwidth Width to word-wrap when using gq Number 80 vim.timeout Timeout in milliseconds for remapped commands Number 1000 vim.whichwrap Allow specified keys that move the cursor left/right to move to the previous/next line when the cursor is on the first/last character in the line....
27 + 343 + 0 = 370, which is equal to the given number; hence it is an Armstrong number. Let’s check four digits Armstrong number: 1634 = (1 * 1 * 1 * 1) + (6 * 6 * 6 * 6) + (3 * 3 * 3 * 3) + (4 * 4 * 4 * 4) ...
Python program to check Armstrong number using object oriented approach# Define a class for Checking Armstrong number class Check : # Constructor def __init__(self,number) : self.num = number # define a method for checking number is Armstrong or not def isArmstrong(self) : # copy num ...
Python program to check ifthe number provided by the userisan Armstrong numberornot # take input from the user num = int(input("Enter a number: ")) # initialise sum sum =0 # find the sum of the cube of each digit temp = num ...