828. Count Unique Characters of All Substrings of a Given String # 题目 # Let’s define a function countUniqueChars(s) that returns the number of unique characters on s, for example if s = "LEETCODE" then "L", "T","C","O","D" are the unique characters
https://leetcode.com/problems/count-unique-characters-of-all-substrings-of-a-given-string/discuss/128952/C%2B%2BJavaPython-One-pass-O(N) https://leetcode.com/problems/count-unique-characters-of-all-substrings-of-a-given-string/discuss/129021/O(N)-Java-Solution-DP-Clear-and-easy-to-Under...
The beauty of a string is the difference in frequencies between the most frequent and least frequent characters. For example, the beauty of"abaacc"is3 - 1 = 2. Given a strings, returnthe sum of beauty of all of its substrings. Example 1: Input: s = "aabcb" Output: 5 Explanation: ...
1890. Sum of Beauty of All Substrings Medium The beauty of a string is the difference in frequencies between the most frequent and least frequent characters. For example, the beauty of "abaacc" is 3 - 1 = 2. Given a string s, return the sum of beauty of all of its substrings. Exa...
[LeetCode] 438. Find All Anagrams in a String 题:https://leetcode.com/problems/find-all-anagrams-in-a-string/description/ 题目 Given a string s and a non-empty string p, find all the start indices of p’s anagrams in s. Strings consists of lowe......
Return the starting indices of all the concatenated substrings ins. You can return the answer inany order. usestd::collections::HashMap;implSolution{pubfnfind_substring(s:String,words:Vec<String>)->Vec<i32>{letwlen=words[0].len();lettotal=s.len();letword_count=words.len();letmutret=...
vector<int> findSubstring(strings, vector<string>& words) { if(words.empty())return{} ; intlenw = words[0].size() ; intszw = words.size() ; intlens = s.size() ; if(lens < szw * lenw)return{} ; unordered_map<string ,int> word ; ...
s中的串联子串是指一个包含words中所有字符串以任意顺序排列连接起来的子串。 例如,如果words = ["ab","cd","ef"], 那么"abcdef","abefcd","cdabef","cdefab","efabcd", 和"efcdab"都是串联子串。"acdbef"不是串联子串,因为他不是任何words排列的连接。
This repo will contain all the solutions of questions that i have solved on leetcode - Akhil-1009/Leetcode-practice-solutions
Input:s="barfoothefoobarman",words=["foo","bar"]Output:[0,9]Explanation:Substrings starting at index0and9are"barfoo"and"foobar"respectively.The output order does not matter,returning[9,0]is fine too. Example 2: 代码语言:javascript