Given a strings, find any substring of length2which is also present in the reverse ofs. Returntrueif such a substring exists, andfalseotherwise. Example 1: Input:s = "leetcode" Output:true Explanation: Substring"ee"is of length2which is also present inreverse(s) == "edocteel". Example ...
代码是js写的,如下: 1varlengthOfLongestSubstring =function(str) {2if(str.length === 0)return0;3varmaxLen = 1; //maximum serial string length4varmaxIdx = 0; //the array sub-index of the last char in the result string5vartmpArr = [0]; //array to save the status data6for(vari ...
You are given a stringsand an array of stringswords. All the strings ofwordsare of the same length. A concatenated string is a string that exactly contains all the strings of any permutation ofwordsconcatenated. For example, ifwords = ["ab","cd","ef"], then"abcdef","abefcd","cdabef...
Can you solve this real interview question? Substring with Concatenation of All Words - You are given a string s and an array of strings words. All the strings of words are of the same length. A concatenated string is a string that exactly contains all
Return the starting indices of all the concatenated substrings ins. You can return the answer inany order. usestd::collections::HashMap;implSolution{pubfnfind_substring(s:String,words:Vec<String>)->Vec<i32>{letwlen=words[0].len();lettotal=s.len();letword_count=words.len();letmutret=...
Can you solve this real interview question? Longest Substring Without Repeating Characters - Given a string s, find the length of the longest substring without duplicate characters. Example 1: Input: s = "abcabcbb" Output: 3 Explanation: The answer
点击这个链接你可以看到更多的解决方法:https://oj.leetcode.com/discuss/6168/my-o-n-solution 下面是我自己的方法,在线AC通过。 classSolution{ public: intlengthOfLongestSubstring(strings) { // Start typing your C/C++ solution below ...
You are given a string, s, and a list of words, words, that are all of the same length. Find all starting indices of substring(s) in s that is a concatenation of each word in words exactly once and without any intervening characters. ...
LeetCode-5 最长回文子串 动态规划(比较笨的一种) Guocx 61 2020.06.22发布于 山西 动态规划 C++ 解题思路动态规划,dp记录i到j字符串中回文的长度代码class Solution { public: string longestPalindrome(string s) { int n = s.size(); // length of string ...
public: string longestPalindrome(string s) { int res_len = 1; int res_max = 0; int res_min = 0; if(s == "") { return ""; } int len = s.size(); int a[len][len]; for(int i = 0; i < len; i++) { ...