在leetcode上刷题的时候,偶然看到一位仁兄总结的关于寻找数组的子集(78,90)、全排列(46,47)、在数组中找出等于固定值的元素的集合(39,40)、找出字符串回文子串的集合(131),感觉很惊喜,所以搬运到这里分享给大家,下边是原文链接,里面也有很多讨论。https://discuss.leetcode.com/topic/46161/a-general-approach-...
在解决LeetCode 0368问题时,如何优化算法效率? Largest Divisible Subset Desicription Given a set of distinct positive integers, find the largest subset such that every pair (Si, Sj) of elements in this subset satisfies: Si % Sj = 0 or Sj % Si = 0. If there are multiple solutions, return...
Leetcode 368. Largest Divisible Subset思路及详解 题目链接:368. Largest Divisible Subset Given a set of distinct positive integers, find the largest subset such that every pair (Si, Sj) of elements in this subset satisfies: Si % Sj = 0 or Sj % Si = 0. If there are mult...
leetcode(78)subset title: leetcode(78)subsetdate: 2019-03-27 13:00:00 +0800update: 2019-03-27 13:00:00 +0800author: mecover: http://ww1.sinaimg.cn/large/006jIRTegy1g1h6hj2mxrj31q512v7wh.jpgpreview: 给定一组不同的整数,nums... ...
LeetCode "Largest Divisible Subset" ! 3031 Very nice DP problem. The key fact of a mutual-divisible subset: if a new number n, is divisible with the largest number m within a mutual-divisible set s, s U {n} is also a mutal-divisible subset....
A set of practice note, solution, complexity analysis and test bench to leetcode problem set - leetcode/Subset_II_by_backtracking.drawio at b58bcceb0ea27d0756ad72fb6a64b3b547fae221 · brianchiang-tw/leetcode
leetcode--Partition Equal Subset Sum分区等子集和问题 第一种解法 dp[j] = dp[j] || dp[j - nums[i]] (nums[i] <= j <= target) 第二种解法 dp[i][j]=dp[i-1][j]|dp[i-1][j-nums[i]] 第三种解法 递归...程序员求职全流程指南 程序员求职全流程指南 转眼校招在即,而金三银四...
[LeetCode] 416. Partition Equal Subset Sum Problem Given a non-empty array containing only positive integers, find if the array can be partitioned into two subsets such that the sum of elements in both subsets is equal. Note: Each of the array element will not exceed 100....
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将数组排序,设长度为n, 维持一个长度为n的dp数组,元素类型为pair<int, int>,pair第一个类型含义是以当前数为结尾的最长divisible subset的长度,第二个类型含义是它的前驱元素。 假如有i, j,其中i> j,如果nums[i]%nums[j],由于nums[j]可以整除它的所有前驱元素,则nums[i]也能整除包括nums[j]在内的...