LeetCode---Add Two Numbers 解法 You are given two non-empty linked lists representing two non-negative integers. The digits are stored in reverse order and each of their nodes contain a single digit. Add the two numbers and return it as a linked list. You may assume the two numbers do ...
AI代码解释 publicstaticListNodeaddTwoNumbers2(ListNode l1,ListNode l2){// 边界条件判断if(l1==null){returnl2;}elseif(l2==null){returnl1;}ListNode list=null;ListNode next=null;// 记录和值int sum=0;// 记录是否有进位int b=0;while(l1!=null||l2!=null){if(l1!=null){sum=l1.val;l1=l1...
6 参考 Add Two Numbers -- LeetCode LeetCode:Add Two Numbers Add Two Numbers leetcode java [LeetCode] Add Two Numbers, Solution
LeetCode-Java-2. Add Two Numbers 题目 You are given two non-empty linked lists representing two non-negative integers. The digits are stored in reverse order and each of their nodes contain a single digit. Add the two numbers and return it as a linked list. 你有两个非空链表,表示两个非...
Java 代码如下: class Solution { public ListNode addTwoNumbers(ListNode l1, ListNode l2) { ListNode dummy = new ListNode(0); ListNode cur = dummy; int carry = 0; while (l1 != null || l2 != null || carry != 0) { int i1 = l1 != null ? l1.val : 0; ...
Javapublic class Solution { public ListNode addTwoNumbers(ListNode l1, ListNode l2) { int carry=0; ListNode listNode=new ListNode(0); ListNode p1=l1,p2=l2,p3=listNode; while(p1!=null||p2!=null){ if(p1!=null){ carry+=p1.val; p1=p1.next; } if(p2!=null){ carry+=p2.val; p2...
class Solution { public: ListNode *addTwoNumbers(ListNode *l1, ListNode *l2) { // Start typing your C/C++ solution below if(l1 == NULL && l2 == NULL) { return NULL; } ListNode *retList = new ListNode(0); ListNode *tmpList = retList; ...
* public class ListNode { * int val; * ListNode next; * ListNode(int x) { val = x; } * } */ class Solution { public ListNode addTwoNumbers(ListNode l1, ListNode l2) { ListNode list = null, s = null; int sum = 0; while (l1 != null || l2 != null) { sum /= 10; if...
Java: classSolution{publicListNodeaddTwoNumbers(ListNodel1,ListNodel2){ListNodedummyHead=newListNode(-1),cur=dummyHead;intsum,carry=0;while(l1!=null||l2!=null){sum=(l1==null?0:l1.val)+(l2==null?0:l2.val)+carry;carry=sum/10;cur.next=newListNode(sum%10);cur=cur.next;if(l1!=null)...
https://leetcode.com/problems/add-two-numbers-ii/discuss/239282/Iterative-O(N)-Time-O(1)-space-without-modifying-input-list-Java-solution 这是我leetcode论坛上的帖子。 这题不难,但是follow up比较苛刻。 follow up要求不能改变input list, 这样我们就不能reverse input list然后从低到高做。