AI代码解释 publicstaticListNodeaddTwoNumbers2(ListNode l1,ListNode l2){// 边界条件判断if(l1==null){returnl2;}elseif(l2==null){returnl1;}ListNode list=null;ListNode next=null;// 记录和值int sum=0;// 记录是否有进位int b=0;while(
6 参考 Add Two Numbers -- LeetCode LeetCode:Add Two Numbers Add Two Numbers leetcode java [LeetCode] Add Two Numbers, Solution
LeetCode---Add Two Numbers 解法 You are given two non-empty linked lists representing two non-negative integers. The digits are stored in reverse order and each of their nodes contain a single digit. Add the two numbers and return it as a linked list. You may assume the two numbers do ...
LeetCode-Java-2. Add Two Numbers 题目 You are given two non-empty linked lists representing two non-negative integers. The digits are stored in reverse order and each of their nodes contain a single digit. Add the two numbers and return it as a linked list. 你有两个非空链表,表示两个非...
[LeetCode-2-Medium] Add Two Numbers 题目要求 You are given two non-empty linked lists representing two non-negative integers. The digits are stored in reverse order and each of their nodes contain a single digit. Add the two numbers and return it as a linked list.You may assume the two...
leetcode算法—两数相加 Add Two Numbers 关注微信公众号:CodingTechWork,一起学习进步。 题目 Add Two Numbers: You are given two non-empty linked lists representing two non-negative integers. The digits are stored in reverse order and each of their nodes contain a single digit. Add the two ...
[Leetcode] Add Two Numbers 链表数相加 Add Two Numbers You are given two linked lists representing two non-negative numbers. The digits are stored in reverse order and each of their nodes contain a single digit. Add the two numbers and return it as a linked list....
Javapublic class Solution { public ListNode addTwoNumbers(ListNode l1, ListNode l2) { int carry=0; ListNode listNode=new ListNode(0); ListNode p1=l1,p2=l2,p3=listNode; while(p1!=null||p2!=null){ if(p1!=null){ carry+=p1.val; p1=p1.next; } if(p2!=null){ carry+=p2.val; p2...
输入: (2 -> 4 -> 3) + (5 -> 6 -> 4)输出: 7 -> 0 -> 8 java实现: /** * Definition for singly-linked list. * public class ListNode { * int val; * ListNode next; * ListNode(int x) { val = x; } * } */ public class Solution { public ListNode...
* public class ListNode { * int val; * ListNode next; * ListNode(int x) { val = x; } * } */ class Solution { public ListNode addTwoNumbers(ListNode l1, ListNode l2) { ListNode list = null, s = null; int sum = 0; while (l1 != null || l2 != null) { sum /= 10; if...