类似题目:LeetCode 67 - Add Binary | 二进制求和 (Rust) 时间复杂度:O(|l1| + |l2|) 需要遍历 l1 中的全部 O(|l1|) 个结点 需要遍历 l2 中的全部 O(|l2|) 个结点 空间复杂度:O(1) 需要为结果链表中的全部 O(max(|l1|, |l2|)) 个结点分配空间 (理论上可以复用已有的结点,这样就只需要定...
题目网址:https://oj.leetcode.com/problems/add-two-numbers/题目描述:You are given two linked lists representing two non-negative numbers. The digits are stored in reverse order and each of their nodes contain a single digit. Add the two numbers and return it as a linked list.Input: (2 -...
leetcode刷题: 002 Add Two Numbers You are given two linked lists representing two non-negative numbers. The digits are stored in reverse order and each of their nodes contain a single digit. Add the two numbers and return it as a linked list....
*/classSolution{public:ListNode*addTwoNumbers(ListNode*l1,ListNode*l2){autoholder=newListNode();autocur=holder;intcarry=0;while(l1!=NULL||l2!=NULL||carry>0){autol1v=l1!=NULL?l1->val:0;autol2v=l2!=NULL?l2->val:0;autovalue=(l1v+l2v+carry)%10;carry=(l1v+l2v+carry)/10;cur->nex...
(node4);ListNode*result2=Solution().addTwoNumbers(node3,node4);printNode(result2,true);printf("---\n");free(node1);free(node2);free(node3);free(node4);free(result1);free(result2);}voidtestSpec(){ListNode*node1=ListNode::nodeWithNumber(0);ListNode*node2=ListNode::nodeWithNumber(...
然后LeetCode 第二题, Add Two Numbers 是一个链表问题 记得最开始看链表问题的时候 看的云里雾里的 当然我本来c++基础就打的很差 指针学的不行 后来也是花了很多的时间来补这方面的知识的 两数相加: 给出两个 非空 的链表用来表示两个非负的整数。其中,它们各自的位数是按照逆序的方式存储的,并且它们的每...
LeetCode 2. Add Two Numbers non-empty You may assume the two numbers do not contain any leading zero, except the number 0 itself. Input: (2 -> 4 -> 3) + (5 -> 6 -> 4) Output: answer: class Solution { public: ListNode* addTwoNumbers(ListNode* l1, ListNode* l2) {...
【LeetCode题解---2】Add Two Numbers 题目 You are given two non-empty linked lists representing two non-negative integers. The digits are stored in reverse order and each of their nodes contain a single digit. Add the two numbers and return it as a linked list....
LeetCode: 2. Add Two Numbers LeetCode: 2. Add Two Numbers 题目描述 You are given two non-empty linked lists representing two non-negative integers. The digits are stored in reverse order and each of their nodes contain a single digit. Add the two numbers and return it as a linked list...
3 输入与输出：/*** Definition for singly-linked list.* struct ListNode {* int val;* ListNode *next;* ListNode(int x) : val(x), next(NULL) {}* };*/class Solution {public: ListNode* addTwoNumbers(ListNode* l1, ListNode* l2) { }};4 解决思路：从表头开始相加，记录每次相加...