LeetCode---Add Two Numbers 解法 You are given two non-empty linked lists representing two non-negative integers. The digits are stored in reverse order and each of their nodes contain a single digit. Add the two numbers and return it as a linked list. You may assume the two numbers do ...
AI代码解释 publicstaticListNodeaddTwoNumbers(ListNode l1,ListNode l2){// 边界条件判断if(l1==null){returnl2;}elseif(l2==null){returnl1;}ListNode head=newListNode(0);ListNode point=head;int carry=0;while(l1!=null&&l2!=null){int sum=carry+l1.val+l2.val;ListNode rest=newListNode(sum%10)...
6 参考 Add Two Numbers -- LeetCode LeetCode:Add Two Numbers Add Two Numbers leetcode java [LeetCode] Add Two Numbers, Solution
leetcode算法—两数相加 Add Two Numbers 关注微信公众号:CodingTechWork,一起学习进步。 题目 Add Two Numbers: You are given two non-empty linked lists representing two non-negative integers. The digits are stored in reverse order and each of their nodes contain a single digit. Add the two numb...
LeetCode-Java-2. Add Two Numbers 题目 You are given two non-empty linked lists representing two non-negative integers. The digits are stored in reverse order and each of their nodes contain a single digit. Add the two numbers and return it as a linked list....
EasyLeetCode 02,两数相加(Add Two Numbers) 作者| 梁唐 大家好,我是梁唐。 题意 题意很简单,给定两个非空的链表。用逆序的链表来表示一个整数,要求我们将这两个数相加,并且返回一个同样形式的链表。 除了数字0之外,这两个数都不会以0开头,也就是没有前导0。
输入: (2 -> 4 -> 3) + (5 -> 6 -> 4)输出: 7 -> 0 -> 8 java实现: /** * Definition for singly-linked list. * public class ListNode { * int val; * ListNode next; * ListNode(int x) { val = x; } * } */ public class Solution { public ListNode...
class Solution { public: ListNode *addTwoNumbers(ListNode *l1, ListNode *l2) { // Start typing your C/C++ solution below if(l1 == NULL && l2 == NULL) { return NULL; } ListNode *retList = new ListNode(0); ListNode *tmpList = retList; ...
Javapublic class Solution { public ListNode addTwoNumbers(ListNode l1, ListNode l2) { int carry=0; ListNode listNode=new ListNode(0); ListNode p1=l1,p2=l2,p3=listNode; while(p1!=null||p2!=null){ if(p1!=null){ carry+=p1.val; p1=p1.next; } if(p2!=null){ carry+=p2.val; p2...
返回使数组元素总和等于goal所需要向数组中添加的最少元素数量,添加元素不应改变数组中abs(nums[i]) <= limit这一属性。 注意,如果x >= 0,那么abs(x)等于x;否则,等于-x。 示例1: 输入:nums = [1,-1,1], limit = 3, goal = -4输出:2解释:可以将 -2 和 -3 添加到数组中,数组的元素总和变为...