AI代码解释 publicstaticListNodeaddTwoNumbers(ListNode l1,ListNode l2){// 边界条件判断if(l1==null){returnl2;}elseif(l2==null){returnl1;}ListNode head=newListNode(0);ListNode point=head;int carry=0;while(l1!=null&&l2!=null){int sum=carry+l1.val+l2.val;ListNode rest=newListNode(sum%10)...
Add Two Numbers II 参考资料: https://leetcode.com/problems/add-two-numbers/ https://leetcode.com/problems/add-two-numbers/discuss/997/c%2B%2B-Sharing-my-11-line-c%2B%2B-solution-can-someone-make-it-even-more-concise LeetCode All in One 题目讲解汇总(持续更新中...)...
LeetCode---Add Two Numbers 解法 You are given two non-empty linked lists representing two non-negative integers. The digits are stored in reverse order and each of their nodes contain a single digit. Add the two numbers and return it as a linked list. You may assume the two numbers do ...
LeetCode-Java-2. Add Two Numbers 题目 You are given two non-empty linked lists representing two non-negative integers. The digits are stored in reverse order and each of their nodes contain a single digit. Add the two numbers and return it as a linked list. 你有两个非空链表,表示两个非...
【LeetCode】2. Add Two Numbers 两数相加 作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.cn/ 个人公众号:负雪明烛 本文关键词:两数相加,链表,求加法,题解,leetcode, 力扣,python, c++, java 目录 题目描述
EasyLeetCode 02,两数相加(Add Two Numbers) 作者| 梁唐 大家好,我是梁唐。 题意 题意很简单,给定两个非空的链表。用逆序的链表来表示一个整数,要求我们将这两个数相加,并且返回一个同样形式的链表。 除了数字0之外,这两个数都不会以0开头,也就是没有前导0。
Javapublic class Solution { public ListNode addTwoNumbers(ListNode l1, ListNode l2) { int carry=0; ListNode listNode=new ListNode(0); ListNode p1=l1,p2=l2,p3=listNode; while(p1!=null||p2!=null){ if(p1!=null){ carry+=p1.val; p1=p1.next; } if(p2!=null){ carry+=p2.val; p2...
class Solution { public: ListNode *addTwoNumbers(ListNode *l1, ListNode *l2) { // Start typing your C/C++ solution below if(l1 == NULL && l2 == NULL) { return NULL; } ListNode *retList = new ListNode(0); ListNode *tmpList = retList; ...
https://leetcode.com/problems/add-two-numbers-ii/discuss/239282/Iterative-O(N)-Time-O(1)-space-without-modifying-input-list-Java-solution 这是我leetcode论坛上的帖子。 这题不难,但是follow up比较苛刻。 follow up要求不能改变input list, 这样我们就不能reverse input list然后从低到高做。
Java: classSolution{publicListNodeaddTwoNumbers(ListNodel1,ListNodel2){ListNodedummyHead=newListNode(-1),cur=dummyHead;intsum,carry=0;while(l1!=null||l2!=null){sum=(l1==null?0:l1.val)+(l2==null?0:l2.val)+carry;carry=sum/10;cur.next=newListNode(sum%10);cur=cur.next;if(l1!=null)...