因为题目中提到a>b>c,a与（2b+3c)的和为0,所以a与(2b+3c)互为相反数，所以a必定大于0，c必定小于0
②-①得:a+b+c=(2a+3b+4c)-(a+2b+3c)=0,即(a+b+c) 2 =a 2 +b 2 +c 2 +2(ab+ca+bc)=0, 则ab+bc+ca=- 1 2 (a 2 +b 2 +c 2), 则原式= ab+bc+ca a 2 + b 2 + c 2 =- 1 2 . 故选A. 点评: 此题考查了完全平方公式,以及分式的化简求值,熟练掌握公式是解本题...
考点： 不等关系与不等式 专题： 不等式的解法及应用 分析： 根据a+2b+3c=0和＞b＞c，得a＞0，c＜0，然后进行判断即可． 因为a＞b＞c，a+2b+3c=0， 所以a＞0，c＜0， 又b＞c，a＞0， 故A正确． 故选A． 点评： 本题主要考查不等式的性质，属于基础...
2b). Notably, molecular phenotypes exhibited a high proportion (an average of 70%) of their own specific molQTL after taking linkage disequilibrium (LD) between SNPs into account (Fig. 2b), indicative of their distinct underlying genetic regulation. On average, 20% of eGenes, 13.5% of s...
2b), which were absent from the Ctrl mice regardless of age (Fig. 2a, c, e, Supplementary Fig. 3a). As time progressed, the fundus lesion size increased and the lesion shape evolved. The fundi eventually had hypo/hyper-pigmented mosaic appearance (Fig. 2d, f, Supplementary Fig. 3b)....
Azure アプリ ID: 2ac58236-2803-420a-95a2-9eba3559b777 [アーティクル] 2024/04/04 このID に関連付けられているアプリ: アプリ名認定AppSource で表示する チャイム V5https://appsource.microsoft.com/product/office/WA200005569
1、a+b+c+d=I(只喜欢1者+只喜欢2者+3者都喜欢+3者都不喜欢=总集)2、a+2b+3c=A+B+C(三个集合相加时，喜欢1者的部分加了1次，2者的部分加了2次，喜欢3者的部分加了3次)3、b+3c=X+Y+Z(题目中的固定表达方式为喜欢A和B的有X人、喜欢A和C的有Y人，喜欢B和C的有Z人)...
zn0I+N3ZTfIP/i110SzxbPBUG+an7g+qFS099YOBl3VCfo33GlNXx2HgciLYA0nn n3UVBRociC9SGKiFf3FsAG7b1+Ms5ukO7hyTP+NaOnKXu0uBuLusE2B8S13M5y5t +pzblXzuCUafkw2ISfK7VKTb2yI7vvWuCuKp5l4A0d2+gZktO7AhgMpOr94Us1y1 k0OFybyKz4UobA5XCGWG4Tdj7QDvnJEfhyDcFyA2eN5mypMX+VS9vxNSoM8lzqw1 ...
There seems to be an issue at embedding images in a pdf file Steps to reproduce error: Paste the following code in the pdfmake/playground The sample file should render OK Download the resulting document Open using Acrobat Reader, I am us...
a+2b=3c，abc分别是：a=3c-2b b=（3c-a）/2 c=（a+2b）/3