要不然f(x)也是个向量.1)f(x)=2(isqrt(3)sinx+jcosx).(icosx+jcosx)+2m-1 =2sqrt(3)sinxcosx+2cosx^2+2m-1 sqrt(3)sin2x+cos2x+2m=2sin(2x+π/6)+2m,最小正周期是π 2)x∈[0,π/2],则2x+π/6∈[π/6,7π/6],当2x+π/6=7π/6时 sin(2x+π/6)取得最小值-1...
∵向量m // 向量p ∴√3sinx/(2√3)=cosx/1 即sinx=2cosx 两边平方得：sin²x=4cos²x 又∵sin²x+cos²x=1 ∴5cos²x=1 即cosx=±√5/5 当cosx=√5/5时,sinx=±2√5/5；当cosx=-√5/5时,sinx=±2√5/5 ∴sinxcosx=±2/5 ...
f(x)=√3*sinxcosx+cos²x =√3/2*sin2x+1/2*(1+cos2x) =√3/2*sin2x+1/2*cos2x+1/2 =sin(2x+π/6)+1/2那么f'(x)=2cos(2x+π/6)≥0所以-π/2+2kπ≤2x+π/6≤π/2+2kπ于是-π/3+kπ≤x≤π/6+kπ即单调递增区间为:[-π/3+kπ,π/6+kπ] 结果...
y=根号3sinx+cosx =2(sinxcos∏/6+cosxsin∏/6)=2sin(x+∏/6)x=2k∏+∏/3,y最大值2 最小正周期2∏ 单调递增区间x∈[2k∏-∏/6,2k∏+5∏/6]
√3sinx+xosx =2[(√3/2)sinx+(1/2)cosx]=2(sinxcos30°+cosxsin30°)=2sin(x+30°)
f(x)=√3sinxcosx-(1/2)cos2x=(√3/2)(2sinxcosx)-(1/2)cos2x =(√3/2)sin2x-(1/2)cos2x=sin2xcosπ/6-cos2xsinπ/6=sin(2x-π/6)
y=根号3sinx+cosx =2*(根号3sinx/2+cosx/2)=2*sin(x+派/6)所以值域是[-2,2],8,函数y=根号三sinx+cosx的值域是多少.详细答案.
cosx+根号3sinx =2（sin30°cosx+cos30°sinx）=2sin(30°+x)化这种同名三角函数的时候，就是配凑成已知角度的值，然后用公式即可
√3sinx+cosx=2.(√3/2sinx+1/2cosx)=2(cos30sinx+sin30cosx)=2sin(30+x)
∵sin2x=2sinxcosx cos2x=2cos²x-1 (二倍角公式) ∴sinxcosx=½sin2x cos²x=(1+cos2x)/2 于是 f(x)=√3sinxcosx-cos²x+1/2 =√3*½sin2x -(1+cos2x)/2+1/2 =√3/2*sin2x-½cos2x-1/2+1/2 =√3/2*sin2x-½cos2x =sin2x cosπ/6-sinπ/6 cos2x =sin(2...