Super A^B mod C 快速幂+欧拉函数降幂 Time Limit:1000MS32768KB64bit IO Format:%I64d & %I64u SubmitStatus Description Given A,B,C, You should quickly calculate the result of A^B mod C. (1<=A,C<=1000000000,1<=B<=10^1000000). Input There are multiply testcases. Each testcase, ther...
1 24 思路:由于B的数据太大,因而我们需要借助欧拉定理来进行降幂,然后再用快速幂解决。 代码实现如下: 1#include <cstdio>2#include <cstring>34constintmaxn = 1e6 +7;5longlonga, b, c;6chars[maxn];78inteuler(intx) {9intans =x;10for(inti =2; i * i <= x; i++) {11if(x % i ...
Given A,B,C, You should quickly calculate the result of A^B mod C. (1<=A,C<=1000000000,1<=B<=10^1000000). Input There are multiply testcases. Each testcase, there is one line contains three integers A, B and C, separated by a single space. Output For each testcase, output an...
快速巧画幂函数的基本图像快速巧画幂函数的基本图像 吴博辉 【期刊名称】《数学学习与研究:教研版》 【年(卷),期】2018(000)005 【摘要】幂函数图像,指数不同,第一象限内必有图像,第四象限必没有图像;画幂函数图像,根据指数取值,分四种情况,先画第一象限,后根据奇偶性,再画对应部分. 【总页数】1页(P96...
Toy(生成函数+Burnside引理+矩阵快速幂) On birthday, Anthony got a toy. It is constructed with N+1(N>=3) balls and 2*N sticks. All balls are in a same plane. One of them is special, while the other N balls are connected to it by N sticks with the same length. The angles ...