y^2=4xy^2=4x,焦点为P/2,0)故椭圆长轴在X轴上,左焦点为(-1,0)a^2-b^2=c^2 a^2=4+1=5 a=√5 故椭圆方程式为(x^2)/5+(y^2)/4=1 长轴为2√5 h-=x=)=h+x,得0=h_G+(fi)/G ,x=2,x=0和(2,-2)根据题意设抛物线方程为y^2=2px =2px则有4=2p*2 则抛物线方程为=2x...
1802.11ax 2x2 160MHz requires use of similarly configured 802.11ax wireless network routers and enables 2402Mbps maximum theoretical data rates (approx. 3X (2.8X) faster than standard 802.11ac 2x2 80MHz (867Mbps) as documented in IEEE 802.11 wireless standard specifications). ...
所以:2x+5y=34^x=(2^2)^x=2^2x32^y=(2^5)^y=2^5y所以:4^x32^y=2^2x 2^5y=2^(2x+5y)=2^3=8 APP内打开 结果2 举报 2x+5Y-3=0所以:2x+5y=34^x=(2^2)^x=2^2x32^y=(2^5)^y=2^5y所以:4^x32^y=2^2x 2^5y=2^(2x+5y)=2^3=8 查看完整答案 结果3 举报 4的X次方等...
Table 2: Intel 10th generation (Ice Lake) U Series and Y Series Processors – Performance features3,4 Feature10th Gen (Ice Lake) Intel Core U Series10th Gen (Ice Lake) Intel Core Y Series CPU/Memory/Graphics Overclocking No No Intel®Extreme Tuning Utility (XTU) ...
(e) The tangent to the graph of y=2x^3+4x^2 has a negative gradient when x=k.Complete the inequality for k.-1.330 to 0.1...k...[2] 相关知识点: 试题来源: 解析 -1.330 to 0.1FT Strict ft of their max point and min point dep on cubic graph or accept corrcct answer from ...
Solve the DE: y' + (3y/x) + 2 = 3x, when f(1) = 1. Solve the DE. y^{(5)} - y^{(4)} + 4y^{(3)} - 4y^{(2)} = e^{2t} Solve the DE: y'' + y' + y = 0, \ y(0) = 1 and y(0)' = 2 Solve the DE. 2x'' + 5x' - 3x = 0 ...
示例 二次方程式 x2−4x−5=0 三角学 4sinθcosθ=2sinθ 线性方程 y=3x+4 算术 699∗533 矩阵 [2534][2−10135] 联立方程 {8x+2y=467x+3y=47 微分 dxd(x−5)(3x2−2) 积分 ∫01xe−x2dx 限制 x→−3limx2+2x−3x2−9 ...
A=∫0−3(2x+2)dx+∫0−3√4−4xdx 1. First Integral: ∫(2x+2)dx=x2+2x∣∣0−3=(0+0)−(9−6)=−3 2. Second Integral: For the integral ∫√4−4xdx, we can use substitution: Let u=4−4x then du=−4dx or dx=−14du. Changing the limits: - When x=...
To find the value of 2x2−3xy when x = -3 and y = 4, plug in -3 for x and plug in 4 for y in the expression: {eq}2x^2 - 3xy \ 2(-3)^2 -...Become a member and unlock all Study Answers Start today. Try it now Create an account Ask a question Our experts can...
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