(5x^1y(1x)+x^5dy)+x^3dx=0 .20.2(ydx+xdy)+xdx-5ydy=0.y(0)=1.21.(xdx+ydy)/(√(1+x^2+y^2)+(ydx-xdy)/(x^2+y^2)=0.22. (ye^x-e^(-y))dx+(xe^(-y)+e^x)dy=0 .23.(1/x-(y^2)/((x-y))^2dx+((x^2)/((x-y)^2)-1/y)dy=0 J一(x-y)dr+((24...
方程可以化为 dy/dx = 3y/x 设y/x = u 有 du = (xdy-ydx) /x^2 整理有 du/dx = (xdy/dx -y )/x^2 x* du/dx +y/x =dy/dx 即 xdu/dx +u =dy/dx xdy-3ydx=0 dy/y=3dx/x ln(y)=3ln(x)+c ln(y/(cx^3))=0 y=cx^3 c为任意常数 ...
Evaluate the line integral ∫Cydx+xdy where C is the parametrized path x=t2,y=t3,1≤t≤3 . Line Integral: An integral that is expressed as the sum of the values of the field at all points on the curve is called a line integral. For example:∫...
直接用格林公式 ∮L xdy-2ydx ＝∫∫D 3 dxdy ＝3∫∫D 1 dxdy ＝3 S(D)＝3×1×1 ＝3 回答完毕求采纳
计算曲线积分I=∫L ydx-xdy\x^2+y^2,其中L:(x-1)^2+(y-... 计算曲线积分I=∫L ydx-xdy\x^2+y^2,其中L:(x-1)^2+(y-1)^2=1(逆时针) 查看答案
你这个是微分方程 原式可变形为4dy/y=-3dx/x 两边同时积分可得4lny=-3lnx+C 即：ln（y^4）=ln[(x^-3)*e^C]所以y^4=(x^-3)*e^C（把e^C整体看成一个常数C）所以y^4*x^3=C 备注：明白了么，这样的题都是把y和dy移到一边，把含x和dx的移到一边，然后积分就可以了 ...