To solve the given problem, we will follow these steps:Step 1: Analyze the first equation We start with the equation: \( x \cos \theta - y \sin \theta = \sqrt{x^2 + y^2} \)Step 2: Rearranging the equation
(xsintheta+ycos theta=4 (x cos theta-ysin theta-2)/((x^(2+y^(2)))(cos^(2)theta+sin^(2)theta))=4^(2)+2^(2) (x^(2)+y^(2)=a^(2)+ b^(2)) (x^(2)+y^(2))(1)=16+4 x^(2)+y^(2)=20
প্রমাণ করো যে, xcos theta+ysin theta=p সরলরেখার অক্ষ দুটির মধ্যবর্তী ছিন্ন অংশের মধ্যবিন্
To solve the given problem, we start with the two equations provided:1. \( \tan \theta = \frac{x \sin \phi}{1 - x \cos \phi} \) 2. \( \tan \phi = \frac{y \sin \theta}{1 - y \cos \theta} \)We need to find the value of \( \frac{x}{...
The elimination of theta from x cos theta+ysin theta=2 and xsin theta-y cos theta=4 will give: x cos theta-ysin theta=2 and xsin theta-y cos theta=4 से thet
If tantheta=(xsinphi)/(1-xcosphi) and tanphi=(ysintheta)/(1-ycostheta), then x/y= (A) sinphi/sintheta (B) sintheta/sinphi (C) sinphi/(1-costheta) (D